The heat will flow towards the air surrounding the soup bowl and towards the countertop below the bowl.
<h3>
Where does the heat go?</h3>
We know that when two bodies of different temperatures there will be a flow of heat between the objects, from the hotter one to the colder one.
In this case, we have the bowl of soup as the hot object, and the ambient (the countertop, the air surrounding the bowl, etc) itself will be the cooler object.
Then the heat will flow towards the air surrounding the soup bowl and towards the countertop below the bowl.
If you want to learn more about heat transfer, you can read:brainly.com/question/12072129
1 revolution = 2π radians
revs = (1/2π) · (rads) / (2π)
revs/sec = (1/2π) · (rads/sec)
RPM = (1/2π) · (rads/min) = (30/π) · (rads/sec)
Answer:
a) t=24s
b) number of oscillations= 11
Explanation:
In case of a damped simple harmonic oscillator the equation of motion is
m(d²x/dt²)+b(dx/dt)+kx=0
Therefore on solving the above differential equation we get,
x(t)=A₀
where A(t)=A₀
A₀ is the amplitude at t=0 and
is the angular frequency of damped SHM, which is given by,
Now coming to the problem,
Given: m=1.2 kg
k=9.8 N/m
b=210 g/s= 0.21 kg/s
A₀=13 cm
a) A(t)=A₀/8
⇒A₀ =A₀/8
⇒
applying logarithm on both sides
⇒
⇒
substituting the values
b)
, where is time period of damped SHM
⇒
let be number of oscillations made
then,
⇒
Answer:
Measurement is a comparison of an unknown quantity with a known fixed quantity of the same kind. The value obtained on measuring a quantity is called its magnitude. The magnitude of a quantity is expressed as numbers in its unit.