Answer:
V2 = 15.53 [m/s]]
Explanation:
In order to solve this problem we must use the principle of energy conservation, where potential energy is transformed into kinetic energy. At the bottom is taken as a reference level of potential energy, where the value of this energy is equal to zero.
Above the inclined plane we have two energies, kinetics and potential. While when the sled is at the reference level all this energy will have been transformed into kinetic energy.
![E_{1}=E_{2}\\ m*g*h+(\frac{1}{2} )*m*v_{1} ^{2}=\frac{1}{2}*m*v_{2} ^{2} \\(9.81*8.21)+(0.5*8.96^{2} )=(0.5*v_{2}^{2} )\\(0.5*v_{2}^{2} )=120.68\\v_{2} ^{2}=241.36\\v_{2} =\sqrt{241.36}\\ v_{2} =15.53[m/s]](https://tex.z-dn.net/?f=E_%7B1%7D%3DE_%7B2%7D%5C%5C%20%20m%2Ag%2Ah%2B%28%5Cfrac%7B1%7D%7B2%7D%20%29%2Am%2Av_%7B1%7D%20%5E%7B2%7D%3D%5Cfrac%7B1%7D%7B2%7D%2Am%2Av_%7B2%7D%20%5E%7B2%7D%20%5C%5C%289.81%2A8.21%29%2B%280.5%2A8.96%5E%7B2%7D%20%29%3D%280.5%2Av_%7B2%7D%5E%7B2%7D%20%29%5C%5C%280.5%2Av_%7B2%7D%5E%7B2%7D%20%29%3D120.68%5C%5Cv_%7B2%7D%20%5E%7B2%7D%3D241.36%5C%5Cv_%7B2%7D%20%3D%5Csqrt%7B241.36%7D%5C%5C%20%20v_%7B2%7D%20%3D15.53%5Bm%2Fs%5D)
Displacement = final - initial
The formula most closely resembling that is delta = xf - xi
Answer:
a) The maximum height the ball will achieve above the launch point is 0.2 m.
b) The minimum velocity with which the ball must be launched is 4.43 m/s or 0.174 in/ms.
Explanation:
a)
For the height reached, we use 3rd equation of motion:
2gh = Vf² - Vo²
Here,
Vo = 3.75 m/s
Vf = 0m/s, since ball stops at the highest point
g = -9.8 m/s² (negative sign for upward motion)
h = maximum height reached by ball
therefore, eqn becomes:
2(-9.8m/s²)(h) = (0 m/s)² - (3.75 m/s²)²
<u>h = 0.2 m</u>
b)
To find out the initial speed to reach the hoop at height of 3.5 m, we again use 3rd eqn. of motion with h= 3.5 m - 2.5m = 1 m (taking launch point as reference), and Vo as unknown:
2(-9.8m/s²)(1 m) = (0 m/s)² - (Vo)²
(Vo)² = 19.6 m²/s²
Vo = √19.6 m²/s²
<u>Vo = 4.43 m/s</u>
Vo = (4.43 m/s)(1 s/1000 ms)(39.37 in/1 m)
<u>Vo = 0.174 in/ms</u>
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Answer:
C
Explanation:
Horizontal is constant... if it was on x axis it would be a speed of 0
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