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choli [55]
3 years ago
7

Using our understanding of orbits, which orbits (near or far) are moving more slowly?

Physics
2 answers:
Vikentia [17]3 years ago
8 0

<u>The closer</u> the planet is to the sun's gravitational pull, <u>the planet will move faster because it takes less time to orbit the sun.</u> The planets <u>that are farther away have less gravitational pull</u>, which means <u>they will move slower and take more time to orbit the sun.</u>

makvit [3.9K]3 years ago
3 0

Using our understanding of orbits, objects in <em>lower, near-in</em> orbits move slower than objects in higher, far-out orbits.

Here's a set of examples:

<u></u>

<u>International Space Station</u> ...

Orbital height -- 254 miles

Speed in Orbit -- 76 mi/sec

<u>Geostationary TV satellite</u> ...

Orbital height -- 22,200 miles

Speed in orbit -- about 1.9 mi/sec

<u>Moon</u> ...

Orbital height -- 238,000 miles

Speed in orbit -- about 0.6 mi/sec

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Weight is measured in units called
Aleksandr-060686 [28]
Pounds

If you are talking about the unit of measurement for weight is that of force it would be Newtons.
8 0
3 years ago
I will mark you brainlist. How can you use a tuning fork to tune a piano?
Phoenix [80]

A tuning fork's job is to establish a single note that everybody can tune to.

Most tuning forks are made to vibrate at 440 Hz, a tone known to musicians as "concert A." To tune a piano, you would start by playing the piano's "A" key while ringing an "A" tuning fork. If the piano is out of tune, you'll hear a distinct warble between the note you're playing and the note played by the tuning fork; the further apart the warbles, the more out-of-tune the piano. By either tightening or loosening the piano's strings, you reduce the warble until it's in line with the tuning fork. Once the "A" key is in tune, you would then adjust all of the instrument's 87 other keys to match. The method is much the same for most other instruments. Whether you're tuning a clarinet or guitar, simply play a concert A and adjust your instrument accordingly

Explanation:

It can be a bit tricky to hold a tuning fork while manipulating an instrument, which is why some musicians decide to clench the base of a ringing tuning fork in their teeth. This has the unique effect of transmitting sound through your bones, allowing your brain to "hear" the tone through your jaw. According to some urban legends, touching your teeth with a vibrating tuning fork is enough to make them explode. It's a myth, obviously, but if you have a cavity or a chipped tooth, you'll quickly find this method to be unbelievably painful.

Luckily, you can also buy tuning forks that come mounted on top of a resonator, a hollow wooden box designed to amplify a tuning fork's vibrations. In 1860, a pair of German inventors even devised a battery-powered tuning fork that musicians didn't need to ring again and again

6 0
3 years ago
Justify why does a bird flap its wing to fly higher??​
SpyIntel [72]

Answer:

they use thermals and air currents to glide.

Explanation:

when they flap higher they use thermals and air currents  because flapping takes a lot of fuel,energy

8 0
3 years ago
Angela has been exercising regularly for two years. Right now at her house everyone is feeling sick, but she is able to help the
Dmitry [639]

Answer:

it make your immune system build up from the strain your puting on you body

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excercise is good for you  and builds muscle and blood cells

3 0
2 years ago
A 0.877-kg ball has an elastic, head-on collision with a second ball that is initially at rest. The second ball moves off with h
Art [367]

Answer: the mass of the second ball is 2.631 kg

Explanation:

Given that;

m1 = 0.877 kg

Initial velocity = V0

Initial momentum = m1 × V0

final velocity of m1 is u1, final velocity of m2 is u2 = v0/2

now final momentum = m1 × u1 + m2 × u2

using momentum conservation;

m1×V0 = m1×u1 + m2×v0/2

m1×(v0 - u1) = m2×V0/2 ----- let this be equation 1

Now, for elastic collision;

m1×v0²/2 = m1×u1²/2 + m2×(v0/2)²/2

m1×(v0² - u1²) = m2×(v0/2)² --------- let this be equation 2

now; equation 2 / equation 1

: V0 + u1 = v0/2

2V0 + 2u1 = V0

2u1 = V0 - 2V0

u1 = -V0/2

now we insert in equ 1

 m1×3V0/2= m2×V0/2

m1 × 3 = m2

m2 = 0.877 × 3

m2 = 2.631 kg

Therefore, the mass of the second ball is 2.631 kg

7 0
3 years ago
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