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VARVARA [1.3K]
1 year ago
12

Solve y^3= −125. y = −5 y = ±5 y = −25 y = ±25

Mathematics
2 answers:
romanna [79]1 year ago
8 0

Answer:

<h3>A. y=-5</h3>

Step-by-step explanation:

Use the order of operations.

PEMDAS stands for:

  • Parentheses
  • Exponents
  • Multiply
  • Divide
  • Add
  • Subtract

Do exponents first.

\sf{y^3=-125}

\sf{x=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\dfrac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\dfrac{-1+\sqrt{3}i}{2}}}

\rightarrow \sf{y=\sqrt[3]{-125},\:y=\sqrt[3]{-125}\dfrac{-1+\sqrt{3}i}{2},\:y=\sqrt[3]{-125}\dfrac{-1-\sqrt{3}i}{2}}

\sf{\sqrt[3]{-125}=\boxed{\sf{-5}}}

Therefore, the correct answer is y=-5.

I hope this helps, let me know if you have any questions.

maks197457 [2]1 year ago
6 0

\huge\text{Hey there!}


\mathsf{y^3 = -125}

\large\text{Solve/take the cube root}

\mathsf{(-125)^{^\dfrac{1}{3}}}\mathsf{ = y}

\mathsf{y = (-125)^{^\dfrac{1}{3}}}

\large\text{Simplify it}

\mathsf{y = -5}


\huge\text{Therefore, your answer is: \boxed{\mathsf{y = -5\ (\rm \bold{O}ption\ A.)}}}\huge\checkmark


\huge\text{Good luck on your assignment \& enjoy your day!}


<h3>~\frak{Amphitrite1040:)}</h3>

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