Answer:
Option (D)
Step-by-step explanation:
Total hours worked of Monday= 4:45 hours + 5:00 hours = 9:45 hours
Total hours worked of Tuesday= 4:45 hours + 4:45 hours = 9:30 hours
Total hours worked of Wednesday= 4:30 hours + 4:30 hours = 9:00 hours
Total hours worked of Thursday= 4:45 hours + 4:15 hours = 9:00 hours
Total hours worked of Friday= 4:45 hours + 4:15 hours = 9:00 hours
Total hours worked = 9:45 + 9:30 + 9:00 + 9:00 + 9:00
= 46:15 hours
≈ 46 hours 15 minutes
Option (D) will be the answer.
Answer:
k ≥ 5
Step-by-step explanation:
Answer:
21,27,33 that's all for now
<u>ANSWER:</u>
The solution set for the inequality 7x < 7(x - 2) is null set 
<u>SOLUTION:</u>
Given, inequality expression is 7x < 7 × (x – 2)
We have to give the solution set for above inequality expression in the interval notation form.
Now, let us solve the inequality expression for x.
Then, 7x < 7 × (x – 2)
7x < 7 × x – 2 × 7
7x < 7x – 14
7x – (7x – 14) < 0
7x – 7x + 14 < 0
0 + 14 < 0
14 < 0
Which is false, so there exists no solution for x which can satisfy the given equation.
So, the interval solution for given inequality will be null set
Hence, the solution set is
Answer:
<em>First.</em> Let us prove that the sum of three consecutive integers is divisible by 3.
Three consecutive integers can be written as k, k+1, k+2. Then, if we denote their sum as n:
n = k+(k+1)+(k+2) = 3k+3 = 3(k+1).
So, n can be written as 3 times another integer, thus n is divisible by 3.
<em>Second. </em>Let us prove that any number divisible by 3 can be written as the sum of three consecutive integers.
Assume that n is divisible by 3. The above proof suggest that we write it as
n=3(k+1)=3k+3=k + k + k +1+2 = k + (k+1) + (k+2).
As k, k+1, k+2 are three consecutive integers, we have completed our goal.
Step-by-step explanation:
