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MA_775_DIABLO [31]
1 year ago
14

Figure b is a scale image of Figure A, as shown. Figure a is an Rectangle with 9 on left side and 12 on bottom of rectangle. and

B is a rectangle 33 on left side and 44 on bottom of rectangle.
.3/11
.3
.11/3
.11
Mathematics
1 answer:
Ronch [10]1 year ago
6 0

The scale factor that was applied to figure A to produce figure B is: 11/3 = 3.67.

<h3>How to Find the Scale Factor of a Dilation?</h3>

The ratio of the corresponding dimensions of the image to the preimage gives the scale factor of any dilation.

That is:

Scale factor = dimension of image (new figure) / corresponding dimension of pre-image (original figure).

The scale factor that was applied to figure A to produce figure B = dimension of figure B / corresponding dimension of figure A.

A dimension of figure B = 33

Corresponding dimension of figure A = 9

Therefore, we would find the scale factor as shown below:

The scale factor that was applied to figure A to produce figure B = 33/9

= 11/3 = 3.67

Therefore, the scale factor that was applied to figure A to produce figure B is: 11/3 = 3.67.

Learn more about the scale factor on:

brainly.com/question/2826496

#SPJ1

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Answer please i need help with this
stellarik [79]

\qquad\qquad\huge\underline{\boxed{\sf Answer}}

Let's evaluate ~

\qquad \sf  \dashrightarrow \: \dfrac{1}{3 {}^{ - 2}   \times {x}^{ - 4} \times  {y}^{2}  }

plug in the values :

\qquad \sf  \dashrightarrow \: \dfrac{1}{3 {}^{ - 2}  \times  {3}^{ - 4}  \times { - 1}^{2}  }

\qquad \sf  \dashrightarrow \: \dfrac{1}{3 {}^{ - 6}  {}^{ } {}^{}  }

\qquad \sf  \dashrightarrow \: {3}^{6}

\qquad \sf  \dashrightarrow \:729

Therefore, B is the Correct choice ~

・ .━━━━━━━†━━━━━━━━━.・

5 0
2 years ago
Read 2 more answers
Helpppppppppppppppppp
irina [24]

Option D:

\left(y^{2}+3 y+7\right)\left(8 y^{2}+y+1\right)=8 y^{4}+25 y^{3}+60 y^{2}+10y+7

Solution:

Given expression is \left(y^{2}+3 y+7\right)\left(8 y^{2}+y+1\right).

<u>To find the product of the expression:</u>

\left(y^{2}+3 y+7\right)\left(8 y^{2}+y+1\right)

Multiply each term of the first term with each term of the 2nd term.

           =y^{2}\left(8 y^{2}+y+1\right) +3 y\left(8 y^{2}+y+1\right) +7\left(8 y^{2}+y+1\right)

Using the exponent rule: a^m \cdot a^n = a^{m+n}

           =\left(8 y^{4}+y^3+y^2\right) +\left(24 y^{3}+3y^2+3y\right) +\left(56 y^{2}+7y+7\right)

           =8 y^{4}+y^3+y^2+24 y^{3}+3y^2+3y+56 y^{2}+7y+7

Arrange the terms with same power.

           =8 y^{4}+y^3+24 y^{3}+y^2+3y^2+56 y^{2}+7y+3y+7

           =8 y^{4}+25 y^{3}+60 y^{2}+10y+7

Hence option D is the correct answer.

\left(y^{2}+3 y+7\right)\left(8 y^{2}+y+1\right)=8 y^{4}+25 y^{3}+60 y^{2}+10y+7

6 0
3 years ago
Juan scored 26 points in the first half of the basketball game, and he scored n points in the second half of the
LUCKY_DIMON [66]
26+N=F
F= final score 
N= points in second half

26+18=F
F=44
8 0
3 years ago
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Svetradugi [14.3K]

Answer:

Step-by-step explanation:

There were three boxes of parts. one weighed 10 pounds, and you know the other two weigh the same. All three together weigh 30 pounds. How much do the two weigh?

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Answer:

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Step-by-step explanation:

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