Answer:
The shape has a total area of 14.96cm²
Step-by-step explanation:
To solve this all you need to do is take the area of the outer rectangle, and subtract the area of the inner rectangle.
The outer rectangle is 5.6 by 6.4 cm. To get its area, just multiply those dimensions. When you do so you get the area 35.84cm².
Next the inner rectangle needs to be subtracted. First though, we need its width, which we're not directly given.
We do however know the width of the entire shape, and the width of segments left after cutting out the inner rectangle. All we need to do then is subtract the later from the former to the the inner rectangle's width:
5.6cm - 1.2cm - 0.8cm = 3.6cm
Great! The inner rectangle has an area of 3.6cm × 5.8cm. That gives us 20.88cm².
The final step is to subtract that 20.88 square cm from the 35.84 that we already have. Doing so gives us a result of 14.96cm², and that is the final answer.
Answer:
m∠A = 9°
Step-by-step explanation:
Answer:
14.7
Step-by-step explanation:
Perhaps your equation is ...
f(t) = N·e^(-0.2174t)
We want f(6) = 4, so ...
4 = N·e^(-0.2174·6) = N·e^-1.3044 ≈ 0.2713N
N = 4/0.2713 = 14.7 . . . . milligrams
The dose amount was about 14.7 mg.
Answer
f(t)=2cos(t)
Step-by-step explanation:
let's describe the situation first, a fly is starting 2 meters from the bulb and flies towards the bulb and when it is really close to the bulb, it flies 2 meters further away from the bulb this means that it reaches d = 0m (distance from the bulb) and then flies further 2 meters so d = -2m.
it this point the fly returns back and touches the bulb and flies away (ends it's oscillatory motion ). d = 0 again and story ends here.
here if we want to model this problem with time function , the cosine function seems the best fit with amplitude of 2, so the answer is f(t) = 2cos(t).
Now you can ask why cosine function? well if you look at the graph or the plot of the function it perfectly captures the physical situation going on here in this problem.
Domain is 0 to 2
because it is one complete cycle and the range is -2 to +2.
