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Brrunno [24]
3 years ago
7

Jim rent a car for the weekend can choose 1 of 2 plans the first plan has $55 initial cost an additional 0.80 per mile driven T

he second plan has no on the song say what it cost $0.90 per mile driven how many miles would you need to drive for the two plans to cost the Same 
Mathematics
1 answer:
Nataly [62]3 years ago
5 0
However many he needs to
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What is the expression in factored form? 9x^2-12x+4​
NNADVOKAT [17]

Answer:

\boxed{\bold{\left(3x-2\right)^2}}

Step By Step Explanation:

  • Rewrite \bold{9x^2-12x+4}

\bold{\left(3x\right)^2-2\cdot \:3x\cdot \:2+2^2}

  • Rewrite Equation

\bold{\left(3x\right)^2-2\cdot \:3x\cdot \:2+2^2}

  • Apply Perfect Square Formula \bold{\left(a-b\right)^2=a^2-2ab+b^2: \ a=3x,\:b=2}

\bold{\left(3x-2\right)^2}

7 0
3 years ago
Read 2 more answers
Hello! If someone could help me answer this it would be appreciated! <3
Leona [35]

Answers:

  • In the top row, the first and third polygons are regular polygons.
  • In the bottom row, only the first polygon is a regular polygon

============================================================

Explanation:

A regular polygon must have all sides of equal length. Also, all angles must be the same measure. This applies to the equilateral triangle in the upper left corner, and the square in the upper right corner. Each angle of the square is 90 degrees even though your teacher didn't use right angle markers.

The middle figure in the top row is not a regular polygon because the sides are not all the same length. Also, the angles are different.

--------------------

In the bottom row, only the first figure is a regular polygon for similar reasons mentioned earlier. The second figure is not a regular polygon because this figure is concave. Only convex polygons can be regular.

The third figure in the bottom row is not regular because one side is longer than the others.

3 0
2 years ago
,/,/,/,//,/,/,/,//,,,,,,///,,/,///,/,,/,,/,/,/,/,,
vladimir2022 [97]

Answer :

hmmm ... :0 ?

3 0
3 years ago
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3. A new process has been developed for applying pho­ toresist to 125-mm silicon wafers used in manufac­ turing integrated circu
dlinn [17]

Answer:

a

The null hypothesis is  H_o : \mu  =  13.4000

The alternative hypothesis is  H_a :  \mu \ne  13.4000

The null hypothesis is rejected

b

The  99% confidence level is   13.3930  < \mu  < 13.3994

Step-by-step explanation:

From the question we are told that

  The sample size is  n =  10

   The  population mean is  \mu =  13.4 000 \  angstroms

   The level of significance is  \alpha =  0.05

   The  sample data is  

13.3987, 13.3957, 13.3902, 13.4015, 13.4001, 13.3918, 13.3965, 13.3925, 13.3946, and 13.4002

Generally the sample mean is mathematically represented as

        \= x =  \frac{13.3987+ 13.3957\cdots +13.4002 }{10}

=>     \= x = 13.3962

Generally the sample standard deviation  is mathematically represented as

    \sigma = \sqrt{\frac{\sum (x_i - \= x)^2}{n} }

=> \sigma = \sqrt{\frac{ (13.3987 - 13.3962)^2 +  (13.3987 - 13.3962)^2 + \cdots + (13.3987 -13.4002)^2  }{10} }

=>  \sigma =0.0039

The null hypothesis is  H_o : \mu  =  13.4000

The alternative hypothesis is  H_a :  \mu \ne  13.4000

Generally the test statistics is mathematically represented as

      z  =  \frac{\= x - \mu}{\frac{\sigma}{\sqrt{n} } }

=>    z  =  \frac{13.3962 -  13.4000}{\frac{0.0039}{\sqrt{10} } }

=>   z =  3.08

Generally the p-value is mathematically represented as

       p-value  = 2P( z   >  3.08)

From the z-table  P(z >  3.08)= 0.001035

So

       p-value  = 2* 0.001035

      p-value  = 0.00207

So from the obtained value we see that

     p-value  < \alpha

Hence the null hypothesis is rejected

Consider the b question

Given that the confidence level is  99%  then the level of significance is

    \alpha =  (100 -99)\%

=> \alpha =  0.01

Generally from the normal distribution table critical value  of  \frac{\alpha }{2} is  

    Z_{\frac{\alpha }{2} } =  2.58

Generally the margin of error is mathematically represented as  

     E =  Z_{\frac{\alpha }{2} } *  \frac{\sigma}{\sqrt{n} }

=>   E = 2.58  *  \frac{0.0039}{\sqrt{10} }

=>    E = 0.00318

Generally the 99% confidence interval is mathematically represented as

     13.3962   - 0.00318  < \mu  < 13.3962   +  0.00318

=>   13.3930  < \mu  < 13.3994

 

7 0
3 years ago
Someone help me pls i will give brainlist<br><br><br><br> write only answers
goldenfox [79]

I hope it's clear enough.

7 0
3 years ago
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