In a chemical bonding the electrons that are in the outer most orbital are the one's involved in bonding. The aim of bonding is that each of the atoms must have an octet of electons ( but there are exception which do not follow this rule ) in their valence orbital in order to become stable.Atoms can either loses, gain or share electrons in order to reach this desired state. In a case where they share, they might share all their valence electrons either with the same or different atoms or a certain number of their electron which will end up with them having eight electrons in their valence orbital. Once the atoms have bonded, the remaining electrons that are not shared between the atoms are called the unshared elctron pair and the electrons that are shared and involved in forming bonds are called the shared electron pair. the unshared electron pair can be shared with another atom that has lost it's electrons, this pair is then called a lone pair.
Acid-base homeostasis is essential to normal function of the human body. Even slight alterations can significantly alter physiologic processes at the tissue and cellular levels. To optimally care for patients, nurses must be able to recognize signs and symptoms that indicate deviations from normal. Nurses who provide infusions to patients-whether in acute care, home care, or infusion center settings-have a responsibility to be able to recognize the laboratory value changes that occur with the imbalance and appreciate the treatment options, including intravenous infusions.
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Lead Oxide
Pb is Lead
O is Oxygen
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Answer:
2, 2, 1
Explanation:
The coefficient of H₂O will be 2 because we have 2 oxygens on the right side but only one on the left side. Now, we have 4 hydrogens on the left side but only 2 on the right side. To balance, we'll add a 2 as the coefficient of H₂. We don't need to change the coefficient of O₂ because the equation is already balanced.
Final answer, 2, 2, 1.
Answer:
d. End product is that product with a ketone and carboxylic acid.
Explanation:
Sodium borohydride is a reducing agent, it reduces the ketone to a primary alcohol.
Then acidified water is an oxidising mixture which reverses the reduction reaction.