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Serhud [2]
3 years ago
11

How many unpaired electrons would you expect for the complex ion: [fe(nh3)6]2+?

Chemistry
2 answers:
Scrat [10]3 years ago
8 0

The complex ions will have 4 unpaired electrons.

Explanation

It is known that in the coordinate complex compound [Fe(NH3)6]2+, the ligand NH3­ exhibit neutral charge so the oxidation state of the transition metal Fe is +2 state in this complex compound.

Now consider the electronic configuration of iron (Fe) at ground state, it is [Ar]3d64s2. So as the Fe is in the form of Fe2+ ions, this means 2 electrons will be removed from the valence shell, thus the resultant electronic configuration after attaining Fe2+ will be [Ar] 3d6.  

Now it is also known that the d orbitals can occupy maximum 10 number of electrons in its 5 lobes which are represented as dxy, dxz, dyz, dx2-y2 and dz2.

As in this case it has only 6 electrons, so according to Pauli's exclusion principle and Aufbau principle, first the five lobes of d subshell will be filled by five unpaired electrons and then the extra 6th electron will be filled in the dxy lobe.

Thus the remaining four lobes will have unpaired electrons leading to formation of four unpaired electrons .

GarryVolchara [31]3 years ago
4 0
The N from NH3 forms a coordinate covalent bond with the metal iron as in this case. The iron itself is at the "center" of the ligate complex ion. Since the net ionic charge is at 2+, it can be said that there is one pair of unpaired electrons for <span>[fe(nh3)6]2+.</span>
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Study the graphs in Figure 6.33 and answer these questions. (see attached image)
Vlad [161]

Hey there :)

The highest solubility of a solute will be when it has the greatest quantity in g when dissolved in 100 g of water. So the solute that is most soluble in water, will have a higher g/100 g water.

1:

a: 0°C - Sucrose will be the solute that is most soluble in water.

b: 80 °C - Also Sucrose will be the most soluble in water.

2:

Yes, as we can see in the graph, sucrose, potassium nitrate, ammonium sulfate and sodium chloride have different solubilities between them and at different temperatures. For example, solubility at 0 °C:

sucrose: 180 g / 100 g of water

potassium nitrate: ~10 g/ 100 g of water

ammonium sulfate: 80 g/100 g water

sodium chloride: 30 g/ 100 g of water

6 0
3 years ago
Please help me.......
NARA [144]

Answer:

what are we suppose to do

Explanation:

7 0
3 years ago
What is an azeotrope and why does it limit ethanol purity, even with fractional distillation?
Flura [38]
<span>An azeotrope is a mixture of two or more liquids whose proportions remain the same when vaporized. Because of this, fractional distillation is unable to purify ethanol.</span>
5 0
3 years ago
An ion is has 5 proton, 7 nuetron, 3+ of what
MArishka [77]

Normally an atom would have the same number of proton and electron in order to be neutral. But an ion has a charge either positive or negative. 3+ meaning that the ion is positive and have 3 less electron compared to the proton. So this ion has 5 proton and 2 electron.

3 0
4 years ago
(a) Calculate the Bohr radius of an electron in the n = 3 orbit of a hydrogen atom.
Nikolay [14]

Explanation:

E_n=-13.6\times \frac{Z^2}{n^2}eV

Formula used for the radius of the n^{th} orbit will be,

r_n=\frac{n^2\times 52.9}{Z}pm   (in pm)

where,

E_n = energy of n^{th} orbit

r_n = radius of n^{th} orbit

n = number of orbit

Z = atomic number

a) The Bohr radius of an electron in the n = 3 orbit of a hydrogen atom.

Z = 1

r_3=\frac{3^2\times 52.9}{1} pm

r_3=476.1 pm

476.1 pm is the Bohr radius of an electron in the n = 3 orbit of a hydrogen atom.

b) The energy (in J) of the atom in part (a)

E_n=-13.6\times \frac{Z^2}{n^2}eV

E_3=-13.6\times \frac{1^2}{3^2}eV=1.51 eV

1 eV=1.60218\times 10^{-19} Joules

1.51 eV=1.51\times 1.60218\times 10^{-19} Joules=2.4210\times 10^{-19} Joules

2.4210\times 10^{-19} Joules is the energy of n = 3 orbit of a hydrogen atom.

c)  The energy of an Li²⁺ ion when its electron is in the n = 3 orbit.

E_n=-13.6\times \frac{Z^2}{n^2}eV

n = 3, Z = 3

E_3=-13.6\times \frac{3^2}{3^2}eV = -13.6 eV

=-13.6eV = -13.6\times 1.60218\times 10^{-19} Joules=2.179\times 10^{-18} Joules

2.179\times 10^{-18} Joules is the energy of an Li²⁺ ion when its electron is in the n = 3 orbit.

d) The difference in answers is due to change value of Z in the formula which is am atomic number of the element..

E_n=-13.6\times \frac{Z^2}{n^2}eV

4 0
3 years ago
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