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2 years ago

A 429 g piece of cheese costs $9.50. What will be the cost for 1.42 kg of this cheese?

Mathematics

1 answer:

stellarik [79]2 years ago

5 0

The cost for 1.42 kg of this cheese will be $ 31.44 .

<h3>What does unit conversion entail?</h3>

The process of translating measurements of a given quantity between different units, frequently using multiplicative conversion factors that change the value of the measured quantity without changing its effects, is known as unit conversion. The specific circumstances and the desired result dictate the conversion process. This may be governed by a regulation, contract, set of technical requirements, or other publicly available standards.

<h3>Why is the unitary technique used? What is it?</h3>

In its simplest form, the unitary procedure is used to determine the value of a single unit from a given multiple.

How to calculate the value of one pen, for example, if 40 cost Rs. 400. To finish it, using the unitary method. Additionally, after the value of a single unit has been established, we can multiply that value by the quantity of additional units required to establish the value of the additional units. This is typically how the concepts of ratio and proportion are used. The unitary method entails calculating the value of a single unit before calculating the value of the required number of units.

Given that 0.429 kg of cheese cost $9.50

As a result, the price of 1 kg of cheese is $9.50/0.429, which is $ 22.14.

As a result, 1.42 kg of cheese will cost you $22.14 * 1.42 = $31.44.

To learn more about unit conversion, tap on the link below:
brainly.com/question/24587372

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What is the distance between the points located at (5, 1) and (10, 11) ?

Feliz [49]

$\large{\underline{\underline{\pmb{\frak {\color {red}{Question:}}}}}}$

$\sf \red{What \: is \: the \: distance \: between \: the \: points \: located \: at \: (5, 1) \: and \: (10, 11) ?}$

$\large{\underline{\underline{\pmb{\frak {\color {blue}{Answer:}}}}}}$

Let, the points be A(5,1) and B(10,11) on the number line.

Here,

$x_{1}$ = 5. $x_{2}$ = 10

$y_{1}$ = 1. $y_{2}$ = 11

We,know that to find distance between two points, the formula is:

$\sqrt{( {x}_{2} - {x}_{1})^{2} + ( {y}_{2} - {y}_{1} )^{2} } \\ \\ = \sqrt{(10 - 5) ^{2} + (11 - 1)^{2} } \\ \\ = \sqrt{ ({5)}^{2} + ( {10})^{2} } \\ \\ = \sqrt{25 + 100} \\ \\ = \sqrt{125} \\ \\ = 11.18$

Therefore, the distance between the two points (A) and (B) is 11.18

$\boxed{ \frak \red{Hope \: it \: helps \: you}}$

4 0

2 years ago

5x3 + 14x2 + 9x <br> help

Cerrena [4.2K]

<h3>Answer: x(x+1)(5x+9) </h3>

===================================================

Work Shown:

5x^3 + 14x^2 + 9x

x( 5x^2 + 14x + 9 )

To factor 5x^2 + 14x + 9, we could use the AC method and guess and check our way to getting the correct result.

A better way in my opinion is to solve 5x^2 + 14x + 9 = 0 through the quadratic formula

$x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-(14)\pm\sqrt{(14)^2-4(5)(9)}}{2(5)}\\\\x = \frac{-14\pm\sqrt{16}}{10}\\\\x = \frac{-14\pm4}{10}\\\\x = \frac{-14+4}{10} \ \text{ or } \ x = \frac{-14-4}{10}\\\\x = \frac{-10}{10} \ \text{ or } \ x = \frac{-18}{10}\\\\x = -1 \ \text{ or } \ x = \frac{-9}{5}\\\\$

Then use those two solutions to find the factorization

x = -1 or x = -9/5

x+1 = 0 or 5x = -9

x+1 = 0 or 5x+9 = 0

(x+1)(5x+9) = 0

So we have shown that 5x^2 + 14x + 9 factors to (x+1)(5x+9)

-----------

Overall,

5x^3 + 14x^2 + 9x

factors to

x(x+1)(5x+9)

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leva [86]

Answer:

The solution for this system is: $x = -1, y = 1$

Step-by-step explanation:

The problem states that we have to solve this system by the elimination method

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In this problem, we have the following system:

$1) -6x + 5y = 1$