The intersection of two sets A and B is defined as the set composed by the elements appearing in both A and B.
So, the intersection is

Because all the other numbers do not belong to both sets:
- 2, 3 and 7 belong to A alone
- 13, 15 and 17 belong to B alone
- 5 and 11 belong to both A and B
Answer:
The answer is 0.106666667
For this case, the first thing you should do is take into account the irrational number definition.
An irrational number is one that can not be written as the quotient between two whole numbers.
Their number of decimals is unlimited and they are not periodic.
An irrational number within the specified domain is:
π/2 = 1.570796327
Answer:
an example of an irrational number that is less than 2 and greater than 1.5 is:
π/2 = 1.570796327
Answer:
D
Step-by-step explanation:
im not sure if they can be the same length, but heres the explanation: so a+b is higher than c, (9=a, 7=b, 11=c) but c is the bigger number by itself. so since a+b is higher added together, it makes it a triangle. sorry if this is wrong but i think its right.
Answer:
y = 2*x^2 - 2*x - 24
Step-by-step explanation:
If we have a quadratic function with roots a and b, we can write the equation for that function as:
y = f(x) = A*(x - a)*(x - b)
Where A is the leading coefficient.
In this case, we know that the roots are: 4 and -3
Then the function will be something like:
f(x) = A*(x - 4)*(x - (-3) )
f(x) = A*(x - 4)*(x + 3)
Now we need to determine the value of A.
We also know that the graph of the function passes through the point (3, -12)
This means that:
f(3) = -12
Then:
-12 = A*(3 - 4)*(3 + 3)
-12 = A*(-1)*(6)
-12 = A*(-6)
-12/-6 = A
2 = A
Then the equation is:
y = f(x) = 2*(x - 4)*(x + 3)
Now we need to write this in standard form, so we just need to expand the equation:
y = f(x) = 2*(x^2 + x*3 - x*4 - 4*3)
y = f(x) = 2*(x^2 - x - 12)
y = f(x) = 2*x^2 - 2*x - 24
Then the relation is:
y = 2*x^2 - 2*x - 24