1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
snow_tiger [21]
3 years ago
10

Answer the following questions about the function whose derivative is f prime​(x)equalsx Superscript negative one third Baseline

(x minus 5 ). a. What are the critical points of​ f? b. On what open intervals is f increasing or​ decreasing? c. At what​ points, if​ any, does f assume local maximum and minimum​ values? a. Find the critical​ points, if any. Select the correct choice below​ and, if​ necessary, fill in the answer box to complete your choice.
Mathematics
1 answer:
Charra [1.4K]3 years ago
8 0

Answer:

a) The critical points for the function include x = 0 and x = 5.

b) The function is increasing when x < 0 and when x > 5.

The function is decreasing when 0 < x < 5.

c) The function has a local minimum at x=5, no known maximum point could be obtained though (no local maximum exists).

Step-by-step explanation:

f'(x) = x⁻⁰•³³³³ (x - 5)

At critical points,

f'(x) = 0

x⁻⁰•³³³³(x - 5) = 0

x⁻⁰•³³³³ = 0 or (x-5) = 0

x = 0 or x = 5

b) A function is said to be increasing when

f'(x) > 0.

and it is said to be decreasing when

f'(x) < 0.

To investigate the region's of increasing or decreasing function.

f'(x) = x⁻⁰•³³³³ (x - 5)

with solutions of x=0 and x=5 at critical points. So, we check the behaviour of f'(x) around the critical points.

x < 0, 0 < x < 5, x > 5

x < 0 | 0 < x < 5 | x > 5 | function

-ve |||| positive ||| +ve | (x⁻⁰•³³³³)

-ve |||| negative || +ve | (x - 5)

+ve | negative | +ve | x⁻⁰•³³³³ (x - 5)

f'(x) = x⁻⁰•³³³(x - 5) > 0 when x < 0 and x > 5.

f'(x) = x⁻⁰•³³³³ (x - 5) < 0 when 0 < x < 5.

c) At maximum point, f"(x) < 0

And at minimum point, f"(x) > 0

f'(x) = x⁻⁰•³³³³ (x - 5) = x⁰•⁶⁶⁷ - 5x⁻⁰•³³³³

f'(x) = x⁰•⁶⁶⁷ - 5x⁻⁰•³³³³

f"(x) = (2/3) x⁻⁰•³³³³ - (-5/3)x⁻¹•³³³³

f"(x) = (2/3) x⁻⁰•³³³³ + (5/3)x⁻¹•³³³³

So, inserting the critical points, 0 and 5

At x = 0,

f"(x) = (2/3) (0)⁻⁰•³³³³ + (5/3)(0)⁻¹•³³³³ = 0.

This means that, the point x = 0 isn't a maximum or minimum point.

At x = 5

f"(x) = (2/3) (5)⁻⁰•³³³³ + (5/3)(5)⁻¹•³³³³

= 0.390 + 0.195 = 0.585 > 0

This corresponds to a minimum point.

Hope this Helps!!!

You might be interested in
You ride a bicycle at a speed of 18 miles per hour. I am 3 miles behind my friend. My friend rides a bicycle at a speed of 12 mi
anzhelika [568]

Answer:

i think 9 but 6 could also be right

Step-by-step explanation:

18-12=6------18-3=15-------15-3=12-----------12-3=9

3 0
3 years ago
Roger and Mary have an online account for buying movies. Roger's account balance is -$25
padilas [110]

Answer:

Rodgers simply because owing 25 dollars is more than 10

5 0
2 years ago
What is the image of point (4, 5) after a counterclockwise rotation of 270º about the origin?
andriy [413]
A <span>counterclockwise rotation of 270º about the origin is equivalent to a </span><span>clockwise rotation of 90º about the origin.

Given a point (4, 5), the x-value, i.e. 4 and the y-value, i.e. 5 are positive, hence the point is in the 1st quadrant of the xy-plane.

A clockwise rotation of </span><span>90º about the origin of a point in the first quadrant of the xy-plane will have its image in the fourth quadrant of the xy-plane. Thus the x-value of the image remains positive but the y-value of the image changes to negative.
Also the x-value and the y-value of the original figure is interchanged.
For example, given a point (a, b) in the first quadrant of the xy-plane, </span><span>a counterclockwise rotation of 270º about the origin which is equivalent to a <span>clockwise rotation of 90º about the origin will result in an image with the coordinate of (b, -a)</span>

Therefore, a </span><span>counterclockwise rotation of 270º about the origin </span><span>of the point (4, 5) will result in an image with the coordinate of (5, -4)</span> (option C)
3 0
3 years ago
Geoffrey wrote the following paragraph proof showing that rectangles are parallelograms with congruent diagonals.
Nonamiya [84]
<span>the answer
The triangle congruence says triangle ERT is congruent to triangle CTR. </span>
4 0
3 years ago
Read 2 more answers
Find x and y pls<br> pls write 20 characters
Ymorist [56]

Answer:

n = 135   m = 45

Step-by-step explanation:

N is 135 and m is on a strait line (180) so if you do 180 - 135 you will get the answer for m.

Hope this helped.

4 0
3 years ago
Other questions:
  • How would you write: two times a number plus one is greater than five and less than seven.?
    10·1 answer
  • 5(4+2x) - (8x-12)=68<br> pls help lol , bad at math
    9·2 answers
  • A restaurant owner is going to panel a square portion of the restaurant's ceiling. The portion to be
    5·1 answer
  • The diagram shows two congruent regular pentagons and part of a regular n-sided polygon A. Two sides of each of the regular pent
    6·1 answer
  • Help Fast Show WORK and. NO links <br> 5f = -75 check your solutio\
    7·2 answers
  • Need answer for this question please.
    9·1 answer
  • The present value of an annuity of 3000 for 15 years at 4.5 % per annum CI is<br>​
    8·1 answer
  • HELP. WILL MAKE BRAINLIEST Make a true congruence statement about the following triangles:
    7·1 answer
  • What is the value? I'm marking brainliest!!
    8·2 answers
  • The area of a triangle is 48cm^2. The height of the triangle is 6cm. Calculate the length of the base
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!