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snow_tiger [21]
3 years ago
10

Answer the following questions about the function whose derivative is f prime​(x)equalsx Superscript negative one third Baseline

(x minus 5 ). a. What are the critical points of​ f? b. On what open intervals is f increasing or​ decreasing? c. At what​ points, if​ any, does f assume local maximum and minimum​ values? a. Find the critical​ points, if any. Select the correct choice below​ and, if​ necessary, fill in the answer box to complete your choice.
Mathematics
1 answer:
Charra [1.4K]3 years ago
8 0

Answer:

a) The critical points for the function include x = 0 and x = 5.

b) The function is increasing when x < 0 and when x > 5.

The function is decreasing when 0 < x < 5.

c) The function has a local minimum at x=5, no known maximum point could be obtained though (no local maximum exists).

Step-by-step explanation:

f'(x) = x⁻⁰•³³³³ (x - 5)

At critical points,

f'(x) = 0

x⁻⁰•³³³³(x - 5) = 0

x⁻⁰•³³³³ = 0 or (x-5) = 0

x = 0 or x = 5

b) A function is said to be increasing when

f'(x) > 0.

and it is said to be decreasing when

f'(x) < 0.

To investigate the region's of increasing or decreasing function.

f'(x) = x⁻⁰•³³³³ (x - 5)

with solutions of x=0 and x=5 at critical points. So, we check the behaviour of f'(x) around the critical points.

x < 0, 0 < x < 5, x > 5

x < 0 | 0 < x < 5 | x > 5 | function

-ve |||| positive ||| +ve | (x⁻⁰•³³³³)

-ve |||| negative || +ve | (x - 5)

+ve | negative | +ve | x⁻⁰•³³³³ (x - 5)

f'(x) = x⁻⁰•³³³(x - 5) > 0 when x < 0 and x > 5.

f'(x) = x⁻⁰•³³³³ (x - 5) < 0 when 0 < x < 5.

c) At maximum point, f"(x) < 0

And at minimum point, f"(x) > 0

f'(x) = x⁻⁰•³³³³ (x - 5) = x⁰•⁶⁶⁷ - 5x⁻⁰•³³³³

f'(x) = x⁰•⁶⁶⁷ - 5x⁻⁰•³³³³

f"(x) = (2/3) x⁻⁰•³³³³ - (-5/3)x⁻¹•³³³³

f"(x) = (2/3) x⁻⁰•³³³³ + (5/3)x⁻¹•³³³³

So, inserting the critical points, 0 and 5

At x = 0,

f"(x) = (2/3) (0)⁻⁰•³³³³ + (5/3)(0)⁻¹•³³³³ = 0.

This means that, the point x = 0 isn't a maximum or minimum point.

At x = 5

f"(x) = (2/3) (5)⁻⁰•³³³³ + (5/3)(5)⁻¹•³³³³

= 0.390 + 0.195 = 0.585 > 0

This corresponds to a minimum point.

Hope this Helps!!!

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