Please answer its urgent‼️‼️‼️

The product of the ages of all teenagers at Joyce’s birthday party last Saturday was 2971987200. The number of 18 year olds who

Elenna [48]

Click here to see ALL problems on Age Word Problems

Question 1128242: The product of the three ages, in years of three teenagers is 4590. None of the teens are the same ages. What are the ages of the three teen ages? (Use guess and check)

A hat and a jacket cost $100. The jacket cost $90 more than the hat. What are the cost of the hat and the cost of the jacket?

Melody picks a number. She doubles the number, squares are result, divide the square by 3 subtracts 30 from the quotient and gets 18. What are the possible numbers that Melody could have picked? What operation does Melody perform that prevents us from knowing 100% certainly which she picked?

(Scroll Down for Answer!)

Did you know that Algebra.Com has hundreds of free volunteer tutors who help people with math homework? Anyone can ask a math question, and most questions get answers!

OR get immediate PAID help on:

Type Your Question

Go!!!

Answer by greenestamps(9721) About Me (Show Source):

You can put this solution on YOUR website!

These are three very different problems. The rules of the forum are one problem per post. Please follow those rules in the future.

(1) Certainly guess and check is the easiest way to solve this problem, since you know the three ages are whole numbers. But you should be able to get to the solution with very few if any wrong "guesses" by making your guesses logically.

The product of the three ages is a multiple of 10, and therefore a multiple of 5; since all three ages are in the teens, one of them has to be 15. Then 4590/15 = 306.

You could do guess and check again from there. However, if you note that both the other ages have to be greater than 15, and you know the last digit of the product has to be "6", then the only possible pair of ages is 17 and 18. And indeed 17*18 is 306.

ANSWER: The ages are 15, 17, and 18.

(2) Here is an informal solution method using logical reasoning.

Take away the "extra" $90 that the jacket costs; you are left with a jacket and a hat that each cost the same, and the total is now $100-$90 = $10. That means each of them costs $5. Now add those extra $90 back on to the price of the jacket.

ANSWER: The jacket costs $95; the hat costs $5.

(3) Melody picks a number: Call it x.

She doubles the number: It is now 2x.

She squares are result: It is now (2x)^2 = 4x^2.

She divides the square by 3: It is now 4x^2/3.

She subtracts 30 from the quotient: It is now 4x^2/3-30.

The number she ends up with is 18.

Solve the equation that says 4x^2/3-30 = 18:

4x%5E2%2F3-30+=+18

4x%5E2%2F3+=+48

4x%5E2+=+144

x%5E2+=+36

x+=+6 or x+=+-6

ANSWER: The two possible starting numbers are 6 and -6. We get two possible answers because of the step where she squares the number.

6 0

2 years ago

Read 2 more answers

What is the slope of the line?<br> 3x-4y=7

Vinvika [58]

Answer:

3/4

Step-by-step explanation:

3x - 4y = 7.....subtract 3x from both sides

-4y = -3x + 7 ...now we divide both sides by -4

(-4/-4)y = (-3/-4)x + (-7/4)...simplify

y = 3/4x - 7/4

y = mx + b

y = 3/4x - 7/4.....so the number in the m position is 3/4 <== ur slope

5 0

3 years ago

Read 2 more answers

What is the confidence interval estimate of the population mean percentage change in the price per share of stock during the fir

I am Lyosha [343]

Answer:

(-0.1059 ; - 0.0337)

Step-by-step explanation:

The data table is attached in the picture below:

These is a matched pair design ; which requires taking the difference of the two values for each sample :

The mean and standard deviation of the difference will be used to construct the confidence interval :

The mean of difference, dbar = Σx/n = - 0.0698

The standard deviation of difference, Sd ;

Sd = [√Σ(d - dbar)²/(n-1)] = 0.1054

n = sample size = 25

The confidence interval :

dbar ± [TCritical * Sd/√n]

Tcritical at 90% ; df = n -1 = 25 -1

Tcritical(90% , 24) = 1.1711

C.I = - 0.0698 ± (1.711 * 0.1054/√25)

C.I = - 0.0698 ± 0.0361

C.I = (-0.1059 ; - 0.0337)

5 0

2 years ago

The royals softball team played 75 games and won 55 of them. What percent of the games did they lose (round to the nearest hundr

dimaraw [331]

If they won 55 of the games, that means they lost the rest of the 75. So,
75 - 55 = 20 games lost. To find the percentage of 20 out of 75, you set up a proportion:

$\frac{20}{75}=\frac{x}{100}$

where x = the percentage of games lost. Cross multiply and divide to isolate the x:

$\frac{20}{75}=\frac{x}{100}\\75x=2000\\75x/75=2000/75\\x=26.6666667$

Rounded to the nearest hundredth, the Royals lost 26.667 % of their games.

3 0

2 years ago

Read 2 more answers

Find the equation of the line that passes through the point (−3, −4) and is parallel to the line that passes through the points

Dimas [21]

Answer:

$y = -\frac{1}{3}x - 5$