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katovenus [111]
1 year ago
9

Find the slope of the line that passes through (5,12) and (9,7)

Mathematics
1 answer:
omeli [17]1 year ago
8 0

The slope will be the difference between the y-coordinates divided by the difference between the x-coordinates:

then the slope of the line is:

m=\frac{12-7}{5-9}=\frac{5}{-4}=-\frac{5}{4}

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Find the area of the region between two concentric circular paths. If the radii of the circular paths are 210 m. and 490 m. resp
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Given :

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Solution :

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\: \qquad  \dashrightarrow \sf{{ \ \dfrac{22}{7} \times   \:490 \times 490 \:  {m}^{2}}}

\: \qquad  \dashrightarrow \sf{{ \ \dfrac{22}{ \cancel{7}} \times   \cancel{490} \times 490 \:  {m}^{2}}}

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Area of the inner circle :

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\: \qquad  \dashrightarrow \sf{{ \ \dfrac{22}{7} \times   \:210 \times 210 \:  {m}^{2}}}

\: \qquad  \dashrightarrow \sf{{ \ \dfrac{22}{ \cancel{7}} \times   \cancel{210} \times 210 \:  {m}^{2}}}

\: \qquad  \dashrightarrow \sf{{ \ {22} \times   30 \times 210 \:  {m}^{2}}}

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⠀

Therefore,

Area of the region inside the circular paths :

\: \qquad  \dashrightarrow \sf{{ \ (754600 - 138600  )  \: {m}^{2}}}

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