Answer:
B. Respiration
Explanation:
cellular respiration is the process where cells use glucose (C6H12O6) and oxygen gas (O2) to make carbon dioxide (CO2) water (H2O) and ATP, which is energy
formula:
C6H12O6 + 6O2 -> 6CO2 + 6H20 + 38ATP
Answer:
React it with CH₃MgBr and work up the product with saturated ammonium chloride solution
Explanation:
Grignard reagents convert esters into tertiary alcohols.
The general equation is
![\text{RCOOR}' \xrightarrow[\text{2. H}^{+}]{\text{1. R$^{\prime \prime}$MgBr}}\text{RR$_{2}^{\prime \prime}$C-OH}](https://tex.z-dn.net/?f=%5Ctext%7BRCOOR%7D%27%20%5Cxrightarrow%5B%5Ctext%7B2.%20H%7D%5E%7B%2B%7D%5D%7B%5Ctext%7B1.%20R%24%5E%7B%5Cprime%20%5Cprime%7D%24MgBr%7D%7D%5Ctext%7BRR%24_%7B2%7D%5E%7B%5Cprime%20%5Cprime%7D%24C-OH%7D)
The Grignard reagent in this synthesis is methylmagnesium bromide. You prepare it by reacting a solution methyl bromide in anhydrous ether with magnesium and a few crystals of iodine.
The reaction consumes 3 mol of CH₃MgBr per mole of dimethyl carbonate, and everything happens in the same pot.
Acid workup of the product usually involves the addition of a saturated aqueous solution of ammonium chloride and extraction with a low-boiling organic solvent.
The mechanism involves:
Step 1. Nucleophilic attack and loss of leaving group
(a) The Grignard reagent attacks the carbonyl of dimethyl carbonate, followed by (b) the loss of a methoxide leaving group.
Step 2. Nucleophilic attack and loss of leaving group
(a) A second mole of the Grignard reagent attacks the carbonyl of methyl acetate, followed by (b) the loss of a methoxide leaving group.
Step 3. Nucleophilic attack and protonation of the adduct.
(a) A third mole of the Grignard reagent attacks the carbonyl of acetone, followed by (b) protonation of the alkoxide to form 2-methylpropan-2-ol.
Answer:
Its conduction
Explanation:
Its when heat is transferred from a object to something else.
:/ do you not have definitions
The temperature in kelvin does 60.5 liters of sulfur dioxide occupy if there are 2.5 mole at 0.75 atm is 221.07 kelvin
Explanation
This is calculated using ideal gas equation, that is PV=nRT
where, P(pressure) = 0.75 atm
V(volume) = 60.5 L
n(moles) = 2.5 mole
R( gas constant) = 0.0821 L.atm/mol.k
T(temperature =?
by making T the subject of the formula
T is therefore =Pv/nR
T= (0.75 atm x 60.5 L) / ( 2.5 molex 0.0821 L.atm/mol.K) = 221.07 kelvins