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andrezito [222]
1 year ago
11

A closed container contains 0.40 moles of argon gas at 25 °C and a pressure of 740 torr. The container is heated to 125 °C and t

he pressure increases. Estimate the number of moles of argon that must be released in order to drop the pressure back to near 740 torr while maintaining the temperature at 125 °C.
Chemistry
1 answer:
Ksivusya [100]1 year ago
7 0

The number of moles of argon that must be released in order to drop.

Solution:

Initial Temperature = 25°c = 298 K

Final Temperature =125 °c = 398 K

Initial Moles (n1) = 0.40 mole

Now,  Using the ideal gas law,

n1T1 = n2T2

0.400×298 = n2 × 398

n2 = 0.299 mol

Moles of Argon released

= 0.400-0.299

= 0.100 mol.

Pressure and force are related. That is using the physical equations if you know the other, you can calculate one using pressure = force/area. This pressure can be reported in pounds per square inch, psi, or Newtons per square meter N/m2. Kinetic energy causes air molecules to move faster. They hit the walls of the container more often and with greater force. The increased pressure inside the can may exceed the strength of the can and cause an explosion.

Learn more about The temperature here:-brainly.com/question/24746268

#SPJ1

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Andreas93 [3]

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React it with CH₃MgBr and work up the product with saturated ammonium chloride solution

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Acid workup of the product usually involves the addition of a saturated aqueous solution of ammonium chloride and extraction with a low-boiling organic solvent.

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Step 2. Nucleophilic attack and loss of leaving group

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8 0
3 years ago
Read 2 more answers
What temperature in kelvin does 60.5 liters of sulfur dioxide occupy if there are 2.5 mol at 0.75 atm??
7nadin3 [17]
 The temperature  in kelvin  does  60.5  liters of sulfur  dioxide  occupy  if there  are  2.5  mole  at 0.75 atm  is   221.07  kelvin 

              Explanation
      This is  calculated using   ideal  gas  equation, that is  PV=nRT
where,  P(pressure)  = 0.75 atm
             V(volume)  = 60.5 L
             n(moles)  = 2.5 mole
             R( gas  constant) = 0.0821 L.atm/mol.k
            T(temperature  =?

by  making   T  the subject   of  the formula  
T  is  therefore =Pv/nR

T= (0.75 atm  x  60.5 L) / (  2.5 molex 0.0821  L.atm/mol.K)  = 221.07 kelvins

6 0
3 years ago
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