Answer:Please find the attachment
Explanation:
Answer:
1.50 g
The heat absorbed by the aluminum in this case is:
q = m x C x ΔT m= q/ (C x ΔT)
q= 9.86 J
C = 0.90 J/g-K
ΔT = ( 30.5 ºC - 23.2 ºC ) = 7.3 ºC = 7.3 K (this is a range of temperature)
m = 9.86 J / ( 0.90 J/g-K ) x 7.3 K ) = 1.50 g
60.052 grams per mole
