Answer:
2.29 g of N2
Explanation:
We have to start with the <u>chemical reaction</u>:
The next step is to <u>balance the reaction</u>:
We can continue with the <u>mol calculation</u> using the molar mass of
(65 g/mol), so:
Now, with the<u> molar ratio</u> between and 
we can <u>calculate the moles</u> of (2:3), so:
With the molar mass of we can <u>calculate the grams</u>:
I hope it helps!
Answer:
molar mass M(s) = 65.326 g/mol
Explanation:
- M(s) + H2SO4(aq) → MSO4(aq) + H2(g)
∴ VH2(g) = 231 mL = 0.231 L
∴ P atm = 1.0079 bar
∴ PvH2O(25°C) = 0.03167 bar
Graham´s law:
⇒ PH2(g) = P atm - PvH2O(25°C)
⇒ PH2(g) = 1.0079 bar - 0.03167 bar = 0.97623 bar = 0.9635 atm
∴ nH2(g) = PV/RT
⇒ nH2(g) = ((0.9635 atm)(0.231 L))/((0.082 atmL/Kmol)(298 K))
⇒ nH2(g) = 9.1082 E-3 mol
⇒ n M(s) = ( 9.1082 E-3 mol H2(g) )(mol M(s)/mol H2(g))
⇒ n M(s) = 9.1082 E-3 mol
∴ molar mass M(s) [=] g/mol
⇒ molar mass M(s) = (0.595 g) / (9.1082 E-3 mol)
⇒ molar mass M(s) = 65.326 g/mol
Answer:
Ethylene glycol
Explanation:
Solubility results when there is some kind of interaction between the solute and its solvent. In the case of ethylene glycol, it could form intermolecular hydrogen bonds with ethanol and is hence miscible with ethanol in all proportions.
