a brick measures of 13 inches i length 10 iches in height and 4 inches in width what is the vlume of the brick

1. Write the equilibrium constant expression for the following:

melisa1 [442]

Answer:

c

Explanation:

it could honestly be wrong but I'm not sure

3 0

3 years ago

Identify the situations that have an unbalanced force

strojnjashka [21]

Answer:

A baseball speeds up as it falls through the air.

A bumper car hit by another car moves off at an angle.

A balloon flies across the room when the air is released.

Explanation:

Let me know if you need any other help

6 0

3 years ago

Convert 99 moles of CO2 to atoms

lorasvet [3.4K]

Answer:

1.78 × 10²⁶ Atoms

Explanation:

Relation between number of molecules and moles is,

No. of Molecules = Moles × 6.022 × 10²³ Molecules/mol

No. of Molecules = 99 mol × 6.022 × 10²³ Molecules/mol

No. of Molecules = 5.96 × 10²⁵ Molecules

Also, In CO₂ Molecule there are 3 atoms.

So,

No. of atoms = 5.96 × 10²⁵ Molecules × 3

No. of atoms = 1.78 × 10²⁶ Atoms

3 0

3 years ago

If you have 85g of sulfur dioxide at STP, how many moles do you have?

Step2247 [10]

Answer: 1.32

Explanation:

Given

85 gm of sulfur dioxide is present at STP

The molar mass of sulfur dioxide is $32+2\times 16=64\ g/mol$

The number of moles of sulfur dioxide is

$\Rightarrow n=\dfrac{85}{64}\\\\\Rightarrow n=1.32\ \text{mol}$

3 0

3 years ago

Explain how changing the concentration The enthalpy change for the reaction, 3CO (g) 2Fe2O3 (s) Imported Asset Fe(s) 3CO2 (g), c

ycow [4]

Answer: For the given equation, only iron has the value of $\Delta H_f$ equal to 0 kJ.

Explanation:

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as $\Delta H^o$

The equation used to calculate enthalpy change is of a reaction is:

$\Delta H^o_{rxn}=\sum [n\times \Delta H^o_f(product)]-\sum [n\times \Delta H^o_f(reactant)]$

For the given chemical reaction:

$3CO(g)+2Fe_2O_3(s)\rightarrow Fe(s)+3CO_2(g)$

The equation for the enthalpy change of the above reaction is:

$\Delta H^o_{rxn}=[(1\times \Delta H^o_f_{(Fe(s))})+(3\times \Delta H^o_f_{(CO_2(g))})]-[(3\times \Delta H^o_f_{(CO(g))})+(2\times \Delta H^o_f_{(Fe_2O_3(s))})]$

The enthalpy of formation for the substances present in their elemental state is taken as 0.

Here, iron is present in its elemental state which is solid.

Hence, for the given equation, only iron has the value of $\Delta H_f$ equal to 0 kJ.

7 0

3 years ago