Answer:
Step-by-step explanation:
We can prove that a tangent will always be perpendicular to the radius touching it. So, the other angle in the diagram is 
.
Because all the angles of a triangle sum to 
, we have that 
.
We combine like terms on the left side to get 
.
We subtract 
on both sides to get 
.
So, 
and we're done!
Answer:
y-1 = f(x)
Step-by-step explanation:
Here, we want to choose the equation for the ref graph
The red graph as we can see is above the black
This means it is more positive
The difference between the two is just 1 unit
By the addition of 1 to the y-value of the black graph, we get the red
Thus, we have that;
y- 1 = f(x)
See the attached figure
DB = 4 and DC = 6 , We need to find AD
Using <span>Euclid's theorem for the right triangle
</span><span>
</span><span>∴ DB² = AD * DC
</span><span>
</span><span>∴ 4² = AD * 6
</span><span>
</span><span>∴ 6 AD = 16
</span><span>
</span><span>
</span><span>
∴ AD = 16/6 = 8/3 ≈ 2.67</span>
To find the average velocity in a velocity-time graph at a particular interval, simply determine the gradient at that particular interval.
<span>a. average velocity= 4/1 </span>
<span>= 4m/s </span>
<span>b. average velocity from 1 to 2.5s= 6/(2.5-1) </span>
<span>= 4m/s </span>
<span>average velocity from 2.5 to 4.0s= 0m/s </span>
<span>average velocity from 0 to 4.0s= (4+0)/4 </span>
<span>= 1m/s </span>
<span>c. average velocity from 1.0 to 4.0s= (4/3)m/s </span>
<span>average velocity from 4.0 to 5.0s= 2/1 </span>
<span>= 2.0m/s </span>
<span>average velocity from 1.0 to 5.0s= ((4/3)+2)/4 </span>
<span>= (5/6)m/s </span>
<span>d. average velocity from 0 to 4.0s= 1.0m/s </span>
<span>average velocity from 4.0 to 5.0s= 2.0m/s </span>
<span>average velocity from 0 to 5.0s= (1.0+2.0)/5 </span>
<span>= (3/5)m/s </span>
Answer:
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