For problem 17, if you double the diameter of the moon, then the surface increases by a factor of 4 and the volume by a factor of 8.
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How to compare the change in surface and volume?</h3>
Let's answer question 17.
Remember that for a sphere of radius R, the volume is:
And the surface area is:
So the volume depends on the cube of the radius and the surface on the square of the radius.
Now, if we double the diameter of the moon, then we also double the radius.
So the new volume will be:
The new volume is 8 times the original volume.
And for the surface:
So the new surface is 4 times the original surface.
If you want to learn more about spheres:
brainly.com/question/10171109
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SOLUTION:
from OA=AB
\theta +\theta 45=180
2\theta =180-45
\theta =\frac{180-45}{2}=67.5
from sin rule,
\frac{OA}{sin\theta }=\frac{AB}{sin\theta }=\frac{OB}{sin45}
\therefore \frac{1}{sin67.5}=\frac{1}{sin67.5}=\frac{OB}{sin45}
\therefore OB=\frac{sin45}{sin67.5}=0.765366864730ml
\therefore net displacement OB=o.77ml
Answer:
the answer is 3sg because it's the only one with out a up side down v and a 2 and if you look at the question it's asking you it has 15sg/- 5g on it put it to together Boom 3sg is your best answer for you
Wow I’ve never seen anything like this before maybe because I’m in 6th grade