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Naily [24]
1 year ago
7

9 A rectangle and a square have the same area. The length

Mathematics
1 answer:
alexira [117]1 year ago
7 0

Answer:

Step-by-step explanation: If the square is 30 ft on one side the other side must be too. So 30x30 = 900. Now, we know the rectangle must also be 900 in area. So, the width must be 10feet and the length must be 90ft because 10x90 is also 900. How I got the length? I did 10x2+70.

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2. Hanna made 5 hit out of 13 during her first baseball game. What percentage of hits did she make?
MrRa [10]

Answer:

B. 38%

Explanation:

Given parameters:

Number of hits = 5hit

Total hits = 13

Unknown:

Percentage of hits shed made = ?

Solution;

The percentage of hit made = \frac{number of hits }{Total hits} x 100

input the parameters and solve;

        Percentage of hit made = \frac{5}{13} x 100

       Percentage of hit = 38%

Percentage of hit = 38%

4 0
3 years ago
Solve y^2+7y+12=0 by completing the square.​
kkurt [141]

Answer:

y = -3, -4

Step-by-step explanation:

Formula is (b/2)^2

So...

(y+7/2)^2 - 1/4 = 0

Add 1/4 to each side

(y+7/2)^2 = 1/4

Square root...

y+7/2 = +-1/2

Add

y = -3, -4

8 0
3 years ago
In this figure, AB¯¯¯¯¯∥CD¯¯¯¯¯ and m∠4=85°.
Stolb23 [73]

AB∥CD and m∠4=85°.

so

<1 = 180° - 85°

<1 = 95°

Because AB∥CD so <5 = <1 = 95° (corresponding angles are equal)

Answer

<5 = 95°

5 0
3 years ago
Read 2 more answers
Find the solutions to the equation by completing the square. x2-6x=7
lianna [129]

Subtract 7 from both sides

x^2 - 6x - 7 = 7 - 7

Simplify

x^2 - 6x - 7 = 0


Answer :

The final solutions to the quadratic equation are:

x = 7, -1
3 0
3 years ago
2x2 – 9x + 2 = –1
Reika [66]

Answer:

C)  The discriminant is greater than 0, so there are two real roots

Step-by-step explanation:

<u>Discriminant</u>

b^2-4ac\quad\textsf{when}\:ax^2+bx+c=0

\textsf{when }\:b^2-4ac > 0 \implies \textsf{two real roots}

\textsf{when }\:b^2-4ac=0 \implies \textsf{one real root}

\textsf{when }\:b^2-4ac < 0 \implies \textsf{no real roots}

2x^2-9x+2=-1

\implies 2x^2-9x+3=0

\implies a=2, b=-9, c=3

\begin{aligned}b^2-4ac &=(-9)^2-4(2)(3)\\& =81-24\\&=57 > 0\implies \textsf{two real roots}\end{aligned}

5 0
2 years ago
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