Multiply. Check for reasonableness.

What is one way to evaluate information from the media?

kifflom [539]

Answer: The answer is (D) distinguish between fact and opinion.

Step-by-step explanation: We are given four options out of which we are to select the correct way to evaluate information from the media.

To evaluate information from the media, we just need to remember two important things about the incident. The first one is the fact and the second one is the opinion, so that we can easily distinguish between both of them and get any information from the media.

Thus, the correct option is (D).

6 0

3 years ago

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In March 2015, the Public Policy Institute of California (PPIC) surveyed 7525 likely voters living in California. In the survey,

balandron [24]

Answer:

$(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}$

And for this case the confidence interval is given by: (0.275, 0.305)

We can estimate the proportion difference as:

$\hat p_D = \frac{0.275+0.305}{2}=0.29$

And the margin of error would be:

$ME=0.305-0.29=0.015$

So then for this case the possibl two options are:

We are 95% confident that the true difference in proportion of Latinos who view global warming as a serious problem and whites who view global warming as a serious problem is 27.5% to 30.5%.

We are 95% confident that the difference between Latino and white opinions about the severity of global warming is 29% with a margin of error of 1.5%.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$p_A$ represent the real population proportion of Latinos who view global warming as a serious problem

$\hat p_A=0.75$ represent the estimated proportion Latinos who view global warming as a serious problem

$n_A$ is the sample size required of Latinos who view global warming as a serious problem

$p_B$ represent the real population proportion of white who view global warming as a serious problem

$\hat p_B =0.46$ represent the estimated proportion of whitewho view global warming as a serious problem

$n_B$ is the sample size required of white

$z$ represent the critical value for the margin of error

Solution to the problem

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}$

And for this case the confidence interval is given by: (0.275, 0.305)

We can estimate the proportion difference as:

$\hat p_D = \frac{0.275+0.305}{2}=0.29$

And the margin of error would be:

$ME=0.305-0.29=0.015$

So then for this case the possibl two options are:

We are 95% confident that the true difference in proportion of Latinos who view global warming as a serious problem and whites who view global warming as a serious problem is 27.5% to 30.5%.

We are 95% confident that the difference between Latino and white opinions about the severity of global warming is 29% with a margin of error of 1.5%.

4 0

3 years ago

I’m almost done with this

Ugo [173]

Answer: Her mom's candle had the stronger scent peppermint is very strong it makes your eyes water

Step-by-step explanation:

4 0

3 years ago

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What is the slope of the line passing through the points (1, –5) and (4, 1)?

MakcuM [25]

The slope would be -2 because you would use the equation m= y2-y1/x2-x1