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1 year ago

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Given the function defined in the table below, find the average rate of change, insimplest form, of the function over the interv

al 6 < x < 15.f(x)017335653971128915107Thank

1 answer:

Reil [10]1 year ago

4 0

To find the average rate of change in a interval

$a\leq x\leq b$

We use the following formula:

$\frac{f(b)-f(a)}{b-a}$

Applying this to our interval

$6\leq x\leq15$

We have the following rate of change:

$\frac{f(15)-f(6)}{15-6}=\frac{107-53}{9}=\frac{54}{9}=6$

We have an average rate of change equals to 6.

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Solving Quadratic Equations with Complex SolutionsThe discriminant: D=b^2-4acQuestion:5x^2-2x+1=0

fomenos

• The value of the discriminant ,D= -16

,

• The solution to the quadratic equation is

$x=\frac{1+2i}{5}\text{ or }\frac{1-2i}{5}$

Step - by - Step Explanation

What to find?

• The discriminant d= b² - 4ac

,

• The solution to the quadratic equation.

Given:

5x² - 2x + 1=0

Comparing the given equation with the general form of the quadratic equation ax² + bx + c=0

a=5 b=-2 and c=1

Uisng the quadratic formula to solve;

$x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

The discriminant D=b² - 4ac

Substitute the values into the discriminant formula and simplify.

D = (-2)² - 4(5)(1)

D = 4 - 20

D = -16

We can now proceed to find the solution of the quadratic equation by substituting into the quadratic formula;

$x=\frac{-(-2)\pm\sqrt[]{-16}}{2(5)}$

Note that:

√-1 = i

$x=\frac{2\pm\sqrt[]{16\times-1}}{10}$

$x=\frac{2\pm\sqrt[]{16}\times\sqrt[]{-1}}{10}$ $x=\frac{2\pm4i}{10}$ $x=\frac{2}{10}\pm\frac{4i}{10}$ $x=\frac{1}{5}\pm\frac{2}{5}i$ $x=\frac{1\pm2i}{5}$

That is;

$\text{Either x=}\frac{1+2i}{5}\text{ or x=}\frac{1-2i}{5}$

7 0

1 year ago

Answer number 58 and answer it CORRECTLY please

Dmitriy789 [7]

The answer is 11 cause if you count the white cubics you get 11 and if you count the shadow with it would be 38 and there is only 11 19 28 171
but i might be wrong

7 0

3 years ago

Please I am on a timer

Mila [183]

Answer: g=5

Step-by-step explanation:

4 0

2 years ago

Select the correct answer.

Genrish500 [490]

B 16 miles an hour

Hope this helps

3 0

2 years ago

find the length of each isosceles right triangle when the hypotenuse is of the given measure given 8cm

Wewaii [24]

It is given that the triangle is isosceles right triangle . And in an isosceles right triangle the legs are equal . Let each leg be of x units. Now we use pythagorean identity, which is

$a^2 +b ^2=c^2$

$x^2 +x^2 = 8^2$

$2x^2 = 64$

$x^2 = 32$

$x = 4 \sqrt 2$

So the length of each leg is $4 \sqrt 2 .$

4 0

3 years ago