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Aleksandr [31]
2 years ago
8

Find the distance between the points (10,10) and (4,10).

Mathematics
1 answer:
Yanka [14]2 years ago
3 0
The formula for distance is :

d = √(x₂-x₁)²+(y₂-y₁)²

Let the point (10;10) be (x₂; y₂) , and let the point (4;10) be (x₁;y₁).

So it would look like this -

d = √(10-4)² + (10-10)²

d = √(6)²+ (0)

d = √36

d = 6 units

Hope this helped~
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Rudy measured an Italian restaurant and made a scale drawing. The scale of the drawing was 1 centimeter : 6 meters. In the drawi
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So I’m assuming you’re saying that 1 cm=6 m so if the kitchen is 4 cm in the drawing it has to be scaled up by 6 for each centimeter. So 4*6=24 so the kitchen is 24 meters long. Hope this helps!
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3 years ago
21. In 4 + In(4x - 15) = In(5x + 19)
Alexxx [7]

Answer:

x=-30;\quad \:I\ne \:0

Step-by-step explanation:

In\cdot \:4+In\left(4x-15\right)=In\left(5x+19\right)

\:4+In\left(4x-15\right):\quad -11nI+4nxI\\In\cdot \:4+In\left(4x-15\right)\\=4nI+nI\left(4x-15\right)\\\\\:In\left(4x-15\right):\quad 4nxI-15nI\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b-c\right)=ab-ac\\a=In,\:b=4x,\:c=15\\=In\cdot \:4x-In\cdot \:15\\=4nxI-15nI\\=In\cdot \:4+4nxI-15nI\\\mathrm{Simplify}\:In\cdot \:4+4nxI-15nI:\quad -11nI+4nxI\\In\cdot \:4+4nxI-15nI\\\mathrm{Group\:like\:terms}\\=4nI-15nI+4nxI\\\mathrm{Add\:similar\:elements:}\:4nI-15nI=-11nI\\=-11nI+4nxI\\

\mathrm{Expand\:}In\left(5x+19\right):\quad 5nxI+19nI\\In\left(5x+19\right)\\=nI\left(5x+19\right)\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b+c\right)=ab+ac\\a=In,\:b=5x,\:c=19\\=In\cdot \:5x+In\cdot \:19\\=5nxI+19nI\\\\-11nI+4nxI=5nxI+19nI\\\\\mathrm{Add\:}11nI\mathrm{\:to\:both\:sides}\\-11nI+4nxI+11nI=5nxI+19nI+11nI\\Simplify\\4nxI=5nxI+30nI\\\mathrm{Subtract\:}5nxI\mathrm{\:from\:both\:sides}\\4nxI-5nxI=5nxI+30nI-5nxI\\\mathrm{Simplify}\\-nxI=30nI\\

\mathrm{Divide\:both\:sides\:by\:}-nI;\quad \:I\ne \:0\\\frac{-nxI}{-nI}=\frac{30nI}{-nI};\quad \:I\ne \:0\\\mathrm{Simplify}\\\frac{-nxI}{-nI}=\frac{30nI}{-nI}\\\mathrm{Simplify\:}\frac{-nxI}{-nI}:\quad x\\\frac{-nxI}{-nI}\\\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{-b}=\frac{a}{b}\\=\frac{nxI}{nI}\\\mathrm{Cancel\:the\:common\:factor:}\:n\\=\frac{xI}{I}\\\mathrm{Cancel\:the\:common\:factor:}\:I\\=x\\\mathrm{Simplify\:}\frac{30nI}{-nI}:\quad -30\\\mathrm{Apply\:the\:fraction\:rule}:

\quad \frac{a}{-b}=-\frac{a}{b}\\\mathrm{Cancel\:the\:common\:factor:}\:n\\=\frac{30I}{I}\\\mathrm{Cancel\:the\:common\:factor:}\:I\\=-30\\x=-30;\quad \:I\ne \:0

3 0
3 years ago
Willing to give brainlyest if you can aswer these for me ASAP<br>​
vichka [17]

Answer:

65

Step-by-step explanation:

its simple math

5 0
2 years ago
Read 2 more answers
Factor the polynomial 8x² - 24x – 224 completely. A- 4(x + 4)(x-7) B- (4x + 16X(12x – 14) C- 8(x + 4)(x - 7) ht D- 2(4x + 16)(x
alisha [4.7K]

Answer:

The correct answer would be...

c. 8(x + 4)(x - 7)

Hope this helps!

8 0
3 years ago
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