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xeze [42]
3 years ago
15

For the geometric series 1 + 3 + 9 + 27 + . . . , find the sum of the first 10 terms.

Mathematics
2 answers:
Archy [21]3 years ago
8 0
First ten terms:
1, 3, 9, 27, 81, 243, 729, 2187, 6561, 19683

You multiply by 3

Sum of the ten terms: 31,711
JulijaS [17]3 years ago
3 0

Answer:

the sum of 1, 3, 9, 27, 81, 243, 729, 2187, 6561, 19683 is  (  29,526  )

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Bill is 15 years older than Paul. Paul is 7 years older than half Milo's age. The sum of all three ages is 85. How old is Bill?
katrin2010 [14]

Answer:

Step-by-step explanation:

Let Milo's age = x

Paul's \ age =\dfrac{1}{2}x+7\\\\\\Bill's \ age = \dfrac{1}{2}x + 7  +15 =\dfrac{1}{2}x+22

Sum of all three ages = 85

x +\dfrac{1}{2}x+7 +\dfrac{1}{2}x+22 = 85\\x +\dfrac{1}{2}x+\dfrac{1}{2}x+7+22 =85\\2x+29=85\\     2x  = 85-29\\\\     2x  = 56\\\\      x = \dfrac{56}{2}\\\\x =28 \ years\\\\\\Bill's \  age =\dfrac{1}{2}x+22 =\dfrac{1}{2}*28+22\\\\\\= 14+22\\

Bill's age = 36 years

6 0
3 years ago
Read 2 more answers
Two step equations that equal 14
Marizza181 [45]

Answer:

x=2

Step-by-step explanation:

2x+10=14

2x=14-10

2x=4

x=4/2

x=2

4 0
3 years ago
Write the equation for the graphed function. I worked out y = 5 - 4 (x + 4)^2 but that isn't right. Any help would be appreciate
alexira [117]

Vertex form for a parabola with vertex (p,q) is

y = a(x-p)^2 + q

We have (p,q)=(-4,5) and another point (-3,2) so we can solve for <em>a:</em>

2 = a(-3 - -4)^2 + 5

2 = a + 5

a = -3

Putting it together,

Answer: y = -3(x + 4)^2 + 5

We could multiply that out if we like but I won't bother.


5 0
3 years ago
4 divided by 5/9 = easy question big points lol
V125BC [204]
7.2 is answer thanks
5 0
3 years ago
Read 2 more answers
Write a translation rule that maps point D ( 7 , − 3 ) onto point D ' ( 2 , 5 ). I NEED HELPPPP!
anzhelika [568]

Answer:

T_{ - 5 ,8} \: or \: D'(x,y) →D(x - 5,y + 8)

Step-by-step explanation:

T _ { ? ,?}

D'(x,y) →D(x \pm ?,y \pm ?)

given D : (7,-3), and D' : (2,5)

the coordinates of D can be represented as (x1,y1), and the coordinates of D' can be represented as (x,y).

you can simply take the difference in the x values and difference in the y values from the preimage to image.

like this:

f'(x,y) → f(x+(x-x1),y+(y-y1)) : T _ {(x-x_1),(y-y_1)}

D'(x,y) → D(x+(2-7),y+(5--3))

D'(x,y) → D(x<u>-5</u>,y<u>+8</u>) : T _ {-5 ,8}

7 0
3 years ago
Read 2 more answers
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