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3 years ago

The radius of a circle is 4 feet. What is the circle's area? Use 3.14 for .

Mathematics

2 answers:

Alenkinab [10]3 years ago

4 0

Answer:

25.12

Step-by-step explanation:

Serga [27]3 years ago

3 0

Answer:

Approximately 50 square feet (50.24 to be exact)

Step-by-step explanation:

If you're using 3.14 for π, and the area of a circle is A=πr2,

(3.14)(4)^2 =?

(3.14)(16) = 50.24

Therefore the answer would be about 50 square feet.

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9+3.5g=11-0.5g brainliest to whoever gives steps

kow [346]

Answer:

The answer is g = 0.5

Step-by-step explanation:

1. Your equation is :

9+3.5g=11-0.5g

2. First, multiply both sides by ten

9 * 10 + 3.5 * 10 = 11 * 10 - 0.5 * 10

3. Next we refine the equation

90 + 35g = 110 - 5g

4. Now, lets subtract 90 from both sides

90 + 35g - 90 = 110 - 5g - 90

5. Simplify

35g + 5g = -5g + 20 + 5g

6. We then add 5g to both sides

35g + 5g = -5g + 20 + 5g

7. Simplify again

40g = 20

8. Now, divide both sides by 40

40g/40 = 20/40

9. And finally, simplify once again to get your final answer.

g = 1/2 or 0.5

I hope this helped :)

7 0

3 years ago

What is /-7/ - /3/ ?

Olenka [21]

Answer:

Step-by-step explanation:

the absolute value of -7 is seven and the absolute value of 3 is 3.

7-3=4

4 0

3 years ago

Find sin2x, cos2x, and tan2x if sinx=-15/17 and x terminates in quadrant III

vodka [1.7K]

Given:

$\sin x=-\dfrac{15}{17}$

x lies in the III quadrant.

To find:

The values of $\sin 2x, \cos 2x, \tan 2x$ .

Solution:

It is given that x lies in the III quadrant. It means only tan and cot are positive and others are negative.

We know that,

$\sin^2 x+\cos^2 x=1$

$(-\dfrac{15}{17})^2+\cos^2 x=1$

$\cos^2 x=1-\dfrac{225}{289}$

$\cos x=\pm\sqrt{\dfrac{289-225}{289}}$

x lies in the III quadrant. So,

$\cos x=-\sqrt{\dfrac{64}{289}}$

$\cos x=-\dfrac{8}{17}$

Now,

$\sin 2x=2\sin x\cos x$

$\sin 2x=2\times (-\dfrac{15}{17})\times (-\dfrac{8}{17})$

$\sin 2x=-\dfrac{240}{289}$

And,

$\cos 2x=1-2\sin^2x$

$\cos 2x=1-2(-\dfrac{15}{17})^2$

$\cos 2x=1-2(\dfrac{225}{289})$

$\cos 2x=\dfrac{289-450}{289}$

$\cos 2x=-\dfrac{161}{289}$

We know that,

$\tan 2x=\dfrac{\sin 2x}{\cos 2x}$

$\tan 2x=\dfrac{-\dfrac{240}{289}}{-\dfrac{161}{289}}$

$\tan 2x=\dfrac{240}{161}$

Therefore, the required values are $\sin 2x=-\dfrac{240}{289},\cos 2x=-\dfrac{161}{289},\tan 2x=\dfrac{240}{161}$ .

7 0

2 years ago

How many ninths in 2/3

GalinKa [24]

6/9 is in 2/3 all you do is multiply numerator and denominator by 3

3 0

3 years ago

Read 2 more answers

If 3 + root8 by 3-root8 + 3-root8 by 3+root8 = a+broot2 find a and b

s2008m [1.1K]

If $\frac{3+\sqrt{8} }{3-\sqrt{8} } +\frac{3-\sqrt{8} }{3+\sqrt{8} }=a+b\sqrt{2}$ , the value of a and b is given as a = 34 and b = 0

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables or numbers.

$\frac{3+\sqrt{8} }{3-\sqrt{8} } +\frac{3-\sqrt{8} }{3+\sqrt{8} }\\ \\\frac{9+6\sqrt{8}+8+9-6\sqrt{8}+8 }{(3-\sqrt{8} )(3+\sqrt{8} )} \\\\\frac{34}{9-8} =34+0\sqrt{2}$

If $\frac{3+\sqrt{8} }{3-\sqrt{8} } +\frac{3-\sqrt{8} }{3+\sqrt{8} }=a+b\sqrt{2}$ , the value of a and b is given as a = 34 and b = 0

Find out more on equation at: brainly.com/question/2972832

#SPJ1

8 0

2 years ago

The radius of a circle is 4 feet. What is the circle's area? Use 3.14 for ​.

The radius of a circle is 4 feet. What is the circle's area? Use 3.14 for .