What are the factors in the expression 4x(3x^2+5y)?

Mathematics

1 answer:

Bess [88]3 years ago

7 0

4x(3x²+5y) expand by distributing terms

4x*3x²+4x*5y take out the constants

(4*3)xx²+4x*5y simplify 4*3 to 12

12xx²+4x*5y use product rule=xᵃxᵇ=xᵃ+ᵇ, and change the two variables (the x's) into ones, because if there is just one variable with no number by it, then it is a one.

12x¹⁺²+4x*5y and simplify 1+2 to 3.

12x³+4x*5y finally simplify 4x*5y to 20xy

12x³+20xy

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Step-by-step explanation:

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