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3 years ago

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What are the factors in the expression 4x(3x^2+5y)?

1 answer:

Bess [88]3 years ago

7 0

4x(3x²+5y) expand by distributing terms

4x*3x²+4x*5y take out the constants

(4*3)xx²+4x*5y simplify 4*3 to 12

12xx²+4x*5y use product rule=xᵃxᵇ=xᵃ+ᵇ, and change the two variables (the x's) into ones, because if there is just one variable with no number by it, then it is a one.

12x¹⁺²+4x*5y and simplify 1+2 to 3.

12x³+4x*5y finally simplify 4x*5y to 20xy

12x³+20xy

Hope this helps, now you know the answer and how to do it. Stay healthy and safe and HAVE A BLESSED AND WONDERFUL DAY! :-)

- Cutiepatutie ☺❀❤

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3 years ago

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A number, y, is equal to twice the sum of a smaller number and 3. The larger number is also equal to 5 more than 3 times the sma

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The equations represent the situation is $y=2x+6$ and $y=5+3x$ .

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Consider the provided information.

First convert the statement into mathematical representation.

Consider the smaller number is <em>x</em> and the larger number is <em>y</em>.

<em>y</em>, is equal to twice the sum of a smaller number and 3.

This information can be written as: $y=2(x+3)$

Which can be further solve as:

$y=2x+6$

The larger number is also equal to 5 more than 3 times the smaller number.

This information can be written as: $y=5+3x$

Thus, the equations represent the situation is $y=2x+6$ and $y=5+3x$ .

Which can be further solve as:

$2x+6=5+3x$

$x=1$

Now, substitute the value of <em>x</em> in $y=5+3x$ .

$y=5+3$

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