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Maurinko [17]
3 years ago
14

Which rule describes the pattern below?

Mathematics
2 answers:
Pepsi [2]3 years ago
6 0
C divide by 4
Hope this helps! :3
Vika [28.1K]3 years ago
4 0
Answer choice C divide by 4. 
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3 groups of how many tenths is 1.5
topjm [15]
Well its 1 and 5 tenths 
- 1.5 = 15 tenths
- 5 groups of 3 is the answer
because 5 x 3 = 15
5 0
3 years ago
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Need the answer on this ​
denpristay [2]
None of the answers are correct because it’s definitely not “Given” because x=20 is like an answer. It’s also not “Distributive Property”, “subtraction Property”, and or “Additional Property” b/c there’s nothing that can be distributed, subtract or add. It’s just an answer.
3 0
3 years ago
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Diane keeps her ribbons in a drawer. She has 3 white ribbons, 6 pink ribbons, 2 yellow ribbons, and 7 blue ribbons. Without look
Akimi4 [234]

Answer:

1/3

Step-by-step explanation:

She has 18 ribbons in total and she has 6 pink ribbons so she has a 6/18 chance or 1/3 chance of pulling a pink ribbon

6 0
2 years ago
businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message
KiRa [710]

Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let <em>X</em> = number of text messages receive or send in an hour.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em>.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: \lambda=\frac{62.7}{24}= 2.6125.

The probability of a random variable can be computed using the formula:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

              = 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

             =1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

6 0
3 years ago
identify the transformations that map rectangle A to rectangle A'. A) reflect over y-axis, reflect over line y = 5, then 3 units
LenaWriter [7]

Answer:7:8

Step-by-step explanation:answer

6 0
3 years ago
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