Answer:
Explanation:
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In this case, since the reaction between sulfuric acid and aluminum hydroxide is:
Whereas the ratio of sulfuric acid to aluminum hydroxide is 3:2; thus, we first compute the moles of sulfuric acid that complete react with 3.209 g of aluminum hydroxide:
Then, given the molarity, it is possible to obtain the milliliters as follows:
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Answer:
The answer to your question is
Explanation:
Data
12.5 g of reactant
Balanced Reaction 1
TiBr₄ + 2H₂ ⇒ Ti + 4HBr
Molar mass of TiBr₄ = 48 + (4 x 80) = 368 g
Atomic mass of Ti = 48 g
Molar mass of HBr = 1 + 80 = 81
368 g of TiBr₄ ---------------- 48 g of Ti
12.5 g of TiBr₄ -------------- x
x = (12.5 x 48) / 368
x = 1.63 g of Ti
368 g of TiBr₄ ----------------4(81) g of HBr
12.5 g of TiBr₄ ------------- x
x = (12.5 x 324) / 368
x = 11 g of HBr
Balanced reaction 2
3SiH₄ + 4NH₃ ⇒ Si₃N₄ + 12H₂
Molar mass of SiH₄ = 28 + 4 = 32
Molar mass of Si₃N₄ = 28 x 3 + 14 x 4 = 84 + 56 = 140 g
Atomic mass of H₂ = 2 g
3(32) g of SiH₄ --------------- 140 g of Si₃N₄
12.5 g of SiH₄ -------------- x
x = 18.2 g of Si₃N₄
3(32) g of SiH₄ --------------- 24 g of H₂
12.5 g of SiH₄ -------------- x
x = 3.125 g of H₂
Answer:
Shorter
Explanation:
As a wavelength increases in size, its frequency, and energy (E) decrease. From these equations, you may realize that as the frequency increases, the wavelength gets shorter. As the frequency decreases, the wavelength gets longer. There are two basic types of waves: mechanical and electromagnetic.
6 protons, 7 neutrons, and if it has no charge then it has 6 electrons
Answer:
Explanation:
<u>1) Mass of carbon (C) in 2.190 g of carbon dioxide (CO₂)</u>
- atomic mass of C: 12.0107 g/mol
- molar mass of CO₂: 44.01 g/mol
- Set a proportion: 12.0107 g of C / 44.01 g of CO₂ = x / 2.190 g of CO₂
x = (12.0107 g of C / 44.01 g of CO₂ ) × 2.190 g of CO₂ = 0.59767 g of C
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<u>2) Mass of hydrogen (H) in 0.930 g of water (H₂O)</u>
- atomic mass of H: 1.00784 g/mol
- molar mass of H₂O: 18.01528 g/mol
- proportion: 2 × 1.00784 g of H / 18.01528 g of H₂O = x / 0.930 g of H₂O
x = ( 2 × 1.00784 g of H / 18.01528 g of H₂O) × 0.930 g of H₂O = 0.10406 g of H
<u>3) Mass of oxygen (O) in 1.0857 g of pure sample</u>
- Mass of O = mass of pure sample - mass of C - mass of H
- Mass of O = 1.0857 g - 0.59767 g - 0.10406 = 0.38397 g O
Round to four decimals: Mass of O = 0.3840 g
<u>4) Mole calculations</u>
Divide the mass in grams of each element by its atomic mass:
- C: 0.59767 g / 12.0107 g/mol = 0.04976 mol
- H: 0.10406 g / 1.00784 g/mol = 0.10325 mol
- O: 0.3840 g / 15.999 g/mol = 0.02400 mol
<u>5) Divide every amount by the smallest value (to find the mole ratios)</u>
- C: 0.04976 mol / 0.02400 mol = 2.07 ≈ 2
- H: 0.10325 mol / 0.02400 mol = 4.3 ≈ 4
- O: 0.02400 mol / 0.02400 mol = 1
Thus the mole ratio is 2 : 4 : 1, and the empirical formula is:
