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elixir [45]
3 years ago
5

For each of the following unbalanced equations, calculate how many grams of each product would be produced by complete reaction

of 12.5 g of the reaction indicated in boldface, indicate clearly the mole ration used for the conversion.a. TiBr₄(g) + H₂(g) \rightarrow Ti(s) + HBr(g)
b. SiH₄(g) + NH₃(g) \rightarrow Si3N₄(s) + H₂(g)
Chemistry
1 answer:
LUCKY_DIMON [66]3 years ago
5 0

Answer:

The answer to your question is

Explanation:

Data

12.5 g of reactant

Balanced Reaction 1

                 TiBr₄ + 2H₂  ⇒  Ti  +  4HBr

Molar mass of TiBr₄ = 48 + (4 x 80) = 368 g

Atomic mass of Ti = 48 g

Molar mass of HBr = 1 + 80 = 81

                 368 g of TiBr₄ ---------------- 48 g of Ti

                    12.5 g of TiBr₄ -------------- x

                    x = (12.5 x 48) / 368

                   x = 1.63 g of Ti

                  368 g of TiBr₄ ----------------4(81) g of HBr

                    12.5 g of TiBr₄ -------------  x

                    x = (12.5 x 324) / 368

                    x = 11 g of HBr

Balanced reaction 2

                  3SiH₄  +  4NH₃  ⇒   Si₃N₄  +  12H₂

Molar mass of SiH₄ = 28 + 4 = 32

Molar mass of Si₃N₄ = 28 x 3 + 14 x 4 = 84 + 56 = 140 g

Atomic mass of H₂ = 2 g

                  3(32) g of SiH₄ --------------- 140 g of Si₃N₄

                    12.5 g of SiH₄ --------------  x

                    x = 18.2 g of Si₃N₄

                  3(32) g of SiH₄ --------------- 24 g of H₂

                  12.5 g of SiH₄   --------------  x

                   x = 3.125 g of H₂

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myrzilka [38]

Answer:

i) ciclobutano

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Explanation:

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La nomenclatura IUPAC es un sistema universalmente aceptado para nombrar compuestos químicos.

los nombres de los compuestos enumerados son;

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3 0
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Ksenya-84 [330]

Thus BeF2 is of most covalent character.

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Now, notice all of our bonds are with F, fluorine, which has the highest electronegativity of 3.98. This means that to determine character we need to consider the electronegativities of the other elements -- whichever has the greatest electronegativity has the least difference and most covalent character.
Na, sodium, has electronegativity of 0.93, so our difference is ~3 -- meaning our bond is ionic. Ca, calcium, has 1.00, leaving our difference to again be ~3 and therefore the bond is ionic. Be, beryllium, has 1.57 yielding a difference of ~2.5, meaning we're still dealing with ionic bond. Cs, cesium, has 0.79, meaning our difference is again ~3 and therefore again our compound is of ionic bond. Lastly, we have Sr, strontium, with an electronegativity of 0.95 and therefore again a difference of roughly 3 and an ionic bond. <span>
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3 0
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sergejj [24]

Answer:

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liq [111]

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