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iragen [17]
3 years ago
14

A 0.1 m solution of which salt is the most basic? (a) nano3 (b) naclo4 (c) nahso4 (d) nahco

Chemistry
1 answer:
lbvjy [14]3 years ago
3 0
Answer is: d) NaHCO₃ - sodium hydrogen carbonate or s<span>odium bicarbonate.
It is because other salt are made in reaction between strong base and strong acid and </span>sodium hydrogen carbonate is made from strong base (sodium hydroxide) and weak acid (carbonic acid).
Sodium bicarbonate<span> is an aqueous solution is used for cases of </span><span>acidosis.</span>
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A 150-lb person burns about 2700 Calories to run a marathon. How much energy is burned in kJ?
Alex17521 [72]
The question above is simply asking us to convert the value from calories into kilojoules. Therefore, we need some factor to multiply to be able to convert it to such units. For calories to kJ, the factor would be 4.184.

2700 cal ( 4.184 kJ/cal) = 11296.8 kJ
5 0
3 years ago
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How<br> many<br> molecules are in 8.55x10-15 moles of a substance
solniwko [45]

Answer:

Know this

1mole of a substance contains 6.022x10²³molecules

Now

8.55x10^-15moles x 6.022x10²³molecules/1mole

=5.15x10^9molecules.

6 0
3 years ago
Please help I’m torn between A and B. I’ve asked many and people say A, but I asked my science teacher and she said B. And also
astraxan [27]
If your science teacher says B, it’s probably because water has a negative and positive end, heat is just a form of energy, as other atoms can’t leave (they’re attracted to the ends) they are being insulated; but notice that ice will melt into gas (where atoms have tons of space) for other atoms to escape. Hence ice and gas aren’t ideal. (Air is a gas here.)
It’s not a 100% but hopefully it helps with some kind of analogy.
4 0
4 years ago
A chemist wants to find Kc for the following reaction at 751 K: 2NH3(g) + 3 I2 (g) LaTeX: \Longleftrightarrow ⟺ 6HI(g) + N2(g) K
charle [14.2K]

<u>Answer:</u> The equilibrium constant for the total reaction is 4.09\times 10^{-6}

<u>Explanation:</u>

We are given:

K_{c_1}=0.282\\\\K_{c_2}=41

We are given two intermediate equations:

<u>Equation 1:</u> N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g);K_{c_1}=0.282

The expression of K_{c_1} for the above equation is:

K_{c_1}=\frac{[NH_3]^2}{[N_2][H_2]^3}

0.282=\frac{[NH_3]^2}{[N_2][H_2]^3}        .......(1)

<u>Equation 2:</u> H_2(g)+I_2(g)\rightleftharpoons 2HI(g);K_{c_2}=41

The expression of K_{c_2} for the above equation is:

K_{c_2}=\frac{[HI]^2}{[H_2][I_2]}

41=\frac{[HI]^2}{[H_2][I_2]}       ......(2)

Cubing both the sides of equation 2, because we need 3 moles of HI in the main expression if equilibrium constant.

(41)^3=\frac{[HI]^6}{[H_2]^3[I_2]^3}

Now, dividing expression 1 by expression 2, we get:

\frac{K_{c_1}}{K_{c_2}}=\left(\frac{\frac{[NH_3]^2}{[N_2][H_2]^3}}{\frac{[HI]^6}{[H_2]^3[l_2]^3}}\right)\\\\\\\frac{0.282}{68921}=\frac{[NH_3]^2[I_2]^3}{[N_2][HI]^6}

\frac{[NH_3]^2[I_2]^3}{[N_2][HI]^6}=4.09\times 10^{-6}

The above expression is the expression for equilibrium constant of the total equation, which is:

2NH_3(g)+3I_2(g)\rightleftharpoons 6HI(g)+N_2;K_c

Hence, the equilibrium constant for the total reaction is 4.09\times 10^{-6}

8 0
3 years ago
Which correctly describes the location and charge of the electrons in an atom
Dmitry [639]
Hey there!


Electrons are negatively charged and orbit the nucleus of the atom on energy levels (kind of in a cloud) :)

(The blue dots on the picture)
3 0
4 years ago
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