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Nikitich [7]
1 year ago
11

Use long division to divide. (x5 + 2x12x² - 5x - 12) = (x² - 3)

Mathematics
1 answer:
12345 [234]1 year ago
4 0

The reminder of the equation using the long division method is 70X - 12.

long division method :

Four main steps to solving this problem:

  • Divide.
  • Multiply.
  • Subtract.
  • Drop down the last digit.

x^2 - 3$\overline{)x^5 + 24x^3- 5x - 12}$( x^3 + 25x\\\\

           x₅ + 3 x³

   <u>       (-)    (-)                               </u>

                 25x³ - 5x   -   12

                 25x³ - 75x

   <u>              (-)      (+)                           </u>

 <u>                           70x  - 12              </u>

here

divisor - (x² - 3)

dividend - (x⁵ + 2x12x² - 5x - 12)

quotient - (x³ +25x)

the given question is incomplete the correct question is

Use long division to divide.

(x⁵ + 2x12x² - 5x - 12) / (x² - 3)

The reminder of the equation using the long division method is 70X - 12.

To know more about division

brainly.com/question/3935316

#SPJ1

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What is a ratio that compares two quantities measured in different units
Lisa [10]
A ratio that compares two quantities measured in different units is a conversion factor!
8 0
3 years ago
Line segment AB has endpoints A(1,8) and B(7,−4). What are the coordinates of the point located 5/6 of the way from A to B?
const2013 [10]

The coordinate of the point is (6,-2)

<h3>How to determine the coordinate of the point?</h3>

The given parameters are:

A = (1,8)

B = (7,-4)

The location of the point (i.e 5/6) means that the ratio is:

m :n = 5 : (6 - 5)

m : n = 5 : 1

The coordinate of the point is then calculated as:

(x,y) = \frac{1}{m + n}* (mx_2 + nx_1,my_2 + ny_1)

So, we have:

(x,y) = \frac{1}{5 + 1}* (5 * 7 + 1 * 1 , 5 * -4 + 1 * 8)

Evaluate

(x,y) = \frac{1}{6}* (36 , -12)

Evaluate the product

(x,y) = (6,-2)

Hence, the coordinate of the point is (6,-2)

Read more abut line segment ratio at:

brainly.com/question/12959377

#SPJ1

6 0
2 years ago
ISTEP IS COMING UP AND IM NOT READY!!!
AlekseyPX

> and < with the lines under it mean that they can also be equal to the constant on the other side (greater/less than or equal to)

So x <= 3 can be anything less than 3 and 3.

*the = in this inequality is the equivalent of a line

Now vice versa.

x => 3 can be anything greater than 3 and 3.

Now for the dots.

The open dots in signs are (< and >).

Basically they start at that point they are on but don't include it.

So an open dot at 3 pointing to the left means that the value is greater than 3 but does not include 3.

The closed dots in signs are (<= and =>).

They start at the point and include it.

So a closed dot a 3 pointing to the left means that the value is greater than 3 and includes 3.

Arrows.

Arrows pointing to the left mean that the values are getting bigger.

Arrows pointing to the right mean that the values are getting smaller.

ie : An arrow pointing to the left with a starting point at 3 = 3 and anything bigger, such as 4.

ie : An arrow pointing to the right with a starting point at 3 = 3 and anything smaller, such as 2.

Solve for problems.

The main concept is isolate the variable.

This basically means make the variable be lonely ^^

Use +, -, *, and /

Ex : 6x + 2 > 3

First, we would subtract 2 from both sides.

6x > 1

Then, we would divide each side by 6, leaving the x alone.

x > 1/6

And voila! x is anything greater than 1/6 but it does not include 1/6.

Hope this helps! ^^

8 0
3 years ago
Read 2 more answers
... please help..........................
Drupady [299]

Answer:

B

Step-by-step explanation:

-8+2=-6 and im pretty sure negative of a power is just a regular power so its B

6 0
3 years ago
1500/semiannual period for 6 years at 2.5%/year compounded semiannually
kari74 [83]

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$1500\\ r=rate\to 2.5\%\to \frac{2.5}{100}\dotfill &0.025\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{semiannual, thus twice} \end{array}\dotfill &2\\ t=years\dotfill &6 \end{cases} \\\\\\ A=1500\left(1+\frac{0.025}{2}\right)^{2\cdot 6}\implies A=1500(1.0125)^{12}\implies A\approx 1741.13

6 0
3 years ago
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