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2 years ago

Find the measure of the indicated angle

Mathematics

2 answers:

emmasim [6.3K]2 years ago

8 0

I think the answer is 23

dsp732 years ago

5 0

Answer:

67°

Step-by-step explanation:

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Find the slope of the line that passes through the following points a(4, -14) b(6, 18)

klemol [59]

Answer:

Slope=16

Step-by-step explanation:

4 0

2 years ago

What to the tenth power can get you 300

OLEGan [10]

Answer:

1.7689 (rounded to 4 decimal places)

Step-by-step explanation:

Let the number we are seeking be "x", thus we can write the equation as:

$x^{10}=300$

Since we have raised "x" to the "10th power", to get "x" back again, we need to take 10th root. Same goes for right side, we take 10th root of 300. We will get our answer. The process shown below:

$x^{10}=300\\\sqrt[10]{x^{10}} =\sqrt[10]{300} \\x=\sqrt[10]{300} \\x=1.7689$

hence, 1.7689 raised to 10th power will give us 300

5 0

2 years ago

The number of withdrawals a bank processes in a day follows a random variable X. The number of deposits in a day is represented

Serhud [2]

Answer:

Check the explanation

Step-by-step explanation:

Number of transactions in a day is sum of number of withdrawals and number of deposits. So,

Number of transactions in a day, Z = X + Y

Moment Generating function of Z is,

T+1

Expected number of transactions in a day = E[Z]

$= \frac{\mathrm{d} }{\mathrm{d} t}_{t=0}M_Z(t) = (r+1)\left ( \frac{p}{1-qe^t} \right )^{r} * \frac{-p}{(1-qe^t)^2} * (-qe^t) for t = 0$

$= (r+1)\left ( \frac{p}{1-qe^0} \right )^{r} * \frac{-p}{(1-qe^0)^2} * (-qe^0)$

$= (r+1)\left ( \frac{p}{1-q} \right )^{r} * \frac{-p}{(1-q)^2} * (-q)$

$= (r+1)\left ( \frac{p}{p} \right )^{r} * \frac{-p}{(p)^2} * (-q)$

$= \frac{(r+1)q}{p}$

4 0

3 years ago

nasty-shy [4]

Answer:

hope this helps :)

5 0

2 years ago

Read 2 more answers

A veteran math teacher at a large high school claims that 93% of their students pass the state’s final exam. A random sample of

Bad White [126]

Answer:

Yes, the probability of seeing the sample result is so far from what is expected that the probability of it occurring by chance alone is very unlikely.

Step-by-step explanation:

I hope this is right

5 0

2 years ago