All categories

2 years ago

Checking my answer again: 11/16 + 1/4

Mathematics

1 answer:

Yuri [45]2 years ago

6 0

15/16 should be the right answer b/c 1/4= 4/16

You might be interested in

What is the value of p in the question below. 10x9/2x4= px 5

ycow [4]

Answer:

p = 5

Step-by-step explanation:

We have that:

$\frac{x^{a}}{x^{b}} = x^{a-b}$

$\frac{x^{9}}{x^{4}} = x^{9-4} = x^{5}$

10/2 = 5

Then

$\frac{10x^{9}}{2x^{4}} = 5x^{9-4} = 5x^{5}$

Finding p:

$5x^{5} = px^{5}$

$p = \frac{5x^{5}}{x^{5}}$

$p = 5$

7 0

2 years ago

What is the quotient of 83.3 and 24.5

Svetradugi [14.3K]

Answer:

3.4

Step-by-step explanation:

83.3 divided by 24.5= 3.4

5 0

2 years ago

Read 2 more answers

Sketch the equilibrium solutions for the following DE and use them to determine the behavior of the solutions.

GREYUIT [131]

Answer:

$y=\dfrac{1}{1-Ke^{-t}}$

Step-by-step explanation:

Given

The given equation is a differential equation

$\dfrac{dy}{dt}=y-y^2$

$\dfrac{dy}{dt}=-(y^2-y)$

By separating variable

⇒ $\dfrac{dy}{(y^2-y)}=-t$

$\left(\dfrac{1}{y-1}-\dfrac{1}{y}\right)dy=-dt$

Now by taking integration both side

$\int\left(\dfrac{1}{y-1}-\dfrac{1}{y}\right)dy=-\int dt$

⇒ $\ln (y-1)-\ln y=-t+C$

Where C is the constant

$\ln \dfrac{y-1}{y}=-t+C$

$\dfrac{y-1}{y}=e^{-t+c}$

$\dfrac{y-1}{y}=Ke^{-t}$

$y=\dfrac{1}{1-Ke^{-t}}$

from above equation we can say that

When t will increases in positive direction then $e^{-t}$ will decreases it means that ${1-Ke^{-t}}$ will increases, so y will decreases. Similarly in the case of negative t.

4 0

2 years ago

Is h(x)=3x^3+2x^2+5 even, odd, or neither?

pochemuha

Answer:

Neither even or odd

Step-by-step explanation:

4 0

2 years ago

Uncle Drew scored 28points in 5 5/6

kap26 [50]

Answer:

it could be 2

Step-by-step explanation:

7 0

2 years ago