None of the given choices is the correct solution.
The setup of the problem is a correct, if somewhat weird, description
of the ideal gas laws, but the temperature involved in the law is the
ABSOLUTE temperature, NOT the Celsius or Fahrenheit one, or
any other scale where 'zero' is not 'Absolute Zero'.
Zero Celsius is (about) 273 Celsius-size degrees above Absolute Zero.
So the original temperature of the gas is (273 + 2.5) = 275.5 Kelvins
(Celsius degrees above absolute zero). THAT's the temperature that's
going to change in inverse proportion to the volume.
(if the pressure doesn't change)
The volume has been multiplied by 100cm³/500cm³ = 1/5 .
Since the temperature changes inversely, it will be multiplied by 5 .
Final absolute temperature = (5) x (original absolute temperature) =
(5) x (275.5 K) =
1377.5 K .
The final Celsius temperature is (1377.5 - 273) = <em>1104.5 °C</em>.
"But those are the choices in the assignment !"
Then the person who wrote the question in the assignment is wrong.
None of the choices they gave is correct.
Answer: 163/27
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
3x + -1/9 = 18
Step 2: Add 1/9 to both sides.
3x + -1/9 + 1/9 + = 18 + 1/9
3x = 163/9
Step 3: Divide both sides by 3.
3x/3 = 163/9 over 3
x = 163/27
To find the solution, simply take 3 and divide it by 12. 3/12 as a fraction would be simplified down to 1/4 or 0.25. Therefore, each student would receive one quarter of a pizza.
Answer:
2 / 5.
Step-by-step explanation:
The slope is the rise over the run.
In this case, the rise is 2 - (-6) = 2 + 6 = 8.
The run is 4 - (-16) = 4 + 16 = 20.
So, the slope is 8 / 20 = 4 / 10 = 2 / 5.
Hope this helps!
Answer:
Explanation:
1)<u> Principal quantum number, n = 2</u>
- n is the principal quantum number and indicates the main energy level.
<u>2) Second quantum number, ℓ</u>
- The second quantum number, ℓ, is named, Azimuthal quantum number.
The possible values of ℓ are from 0 to n - 1.
Hence, since n = 2, there are two possible values for ℓ: 0, and 1.
This gives you two shapes for the orbitals: 0 corresponds to "s" orbitals, and 1 corresponds to "p" orbitals.
<u>3) Third quantum number, mℓ</u>
- The third quantum number, mℓ, is named magnetic quantum number.
The possible values for mℓ are from - ℓ to + ℓ.
Hence, the poosible values for mℓ when n = 2 are:
- for ℓ = 1, mℓ = -1, 0, or +1.
<u>4) Fourth quantum number, ms.</u>
- This is the spin number and it can be either +1/2 or -1/2.
Therfore the full set of possible states (different quantum number for a given atom) for n = 2 is:
- (2, 0, 0 +1/2)
- (2, 0, 0, -1/2)
- (2, 1, - 1, + 1/2)
- (2, 1, -1, -1/2)
- (2, 1, 0, +1/2)
- (2, 1, 0, -1/2)
- (2, 1, 1, +1/2)
- (2, 1, 1, -1/2)
That is a total of <u>8 different possible states</u>, which is the answer for the question.
