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aniked [119]
1 year ago
9

Write in a number in which the value of the 8 is ten times greater than the value of the 8 in 8304?

Mathematics
1 answer:
Serhud [2]1 year ago
6 0

Thee number in which case has the value of the 8 ten times greater than than the value of the 8 in 8304 as required in the task content is; 83450.

<h3>Which number has the value of the 8 is ten times greater than the value of the 8 in 8304?</h3>

It follows from the task content that the number which satisfies the condition that, the value of its 8 is ten times greater than the value of the 8 in 8304 is to be determined.

It follows from place value that the 8 in 8304 has a value of; 8 × 1000 = 8000.

Hence, an example of a number that is ten times greater is; 10 × 80,000.

Ultimately, an example of the required number as in the task content is; 83450 where it's 8 digit is ten times greater than that in 8304.

Read more on place value;

brainly.com/question/569339

#SPJ1

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Prove algebraically that r = 10/2+2sinTheta is a parabola
Xelga [282]

Answer:

y =  -  \frac{ 1 }{10} {x}^{2}   +  \frac{5}{2}

Step-by-step explanation:

We want to prove algebraically that:

r =  \frac{10}{2 + 2 \sin \theta}

is a parabola.

We use the relations

{r}^{2}  =  {x}^{2}  +  {y}^{2}

and

y = r \sin \theta

Before we substitute, let us rewrite the equation to get:

r(2 + 2 \sin \theta) = 10

Or

r(1+  \sin \theta) = 5

Expand :

r+  r\sin \theta= 5

We now substitute to get:

\sqrt{ {x}^{2}  +  {y}^{2} }  + y = 5

This means that:

\sqrt{ {x}^{2}  +  {y}^{2} }=5 - y

Square:

{x}^{2}  +  {y}^{2} =(5 - y)^{2}

Expand:

{x}^{2}  +  {y}^{2} =25 - 10y +  {y}^{2}

{x}^{2}  =25 - 10y

{x}^{2}  - 25 =  - 10y

y =  -  \frac{ {x}^{2} }{10}  +  \frac{5}{2}

This is a parabola (0,2.5) and turns upside down.

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3 years ago
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Answer:

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: A personal computer manufacturer buys 36% of its chips from Japan and the rest from the United St...
meriva

Answer: 0.9862

Step-by-step explanation:

Given : The probability that the chips belongs to Japan: P(J)= 0.36

The probability that the chips belongs to United States : P(U)= 1-0.36=0.64

The proportion of Japanese chips are defective : P(D|J)=0.017

The proportion of American chips are defective : P(D|U)=0.012

Using law of total probability , we have

P(D)=P(D|J)\times P(J)+P(D|U)\times P(U)\\\\\Rightarrow\ P(D)=0.017\times0.36+0.012\times0.64=0.0138

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