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FinnZ [79.3K]
3 years ago
5

QF Q6.) Find the following function for c.

Mathematics
2 answers:
GarryVolchara [31]3 years ago
8 0
\text{Solution for} f(x)=2x-2 and g(x)=5x^2-3

\dfrac{d}{dx}  \left(2x-2\right)=2 \ \ \     =\ \textgreater \   \ \ \ \dfrac{d}{dx}\left(2x\right)-\dfrac{d}{dx}\left(2\right) 

2\dfrac{d}{dx}\left(x\right)   = 2 

\dfrac{d}{dx}\left(2\right) = 0 

\text{Therefore, 2 - 0 = 2}

_____________________________________________________

\dfrac{d}{dx}\left(5x^2\right)-\dfrac{d}{dx}\left(3\right) 

5\dfrac{d}{dx}\left(x^2\right) =\ \textgreater \  5 * \:2x =\ \textgreater \  10x 

<span>5*2^2 -3 

</span><span>g(f(2)) = 17 

</span>2*17 -2 = 32&#10; 

hammer [34]3 years ago
7 0
(f∘g)(x) = f(g(x))
(f∘g)(2) = f(g(2)) = f(5·2² -3) = f(17) = 2·17 -2 = 32

(f∘g)(2) = 32
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Brian tied a 136-foot rope around the perimeter of his rectangular house. He knows that the length of the house is 10 feet less
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Answer:

length 42 cm and width 26 cm

Step-by-step explanation:

Given

Since Brian tied 136 foot rope around the perimeter , hence perimeter of house is 136 foot.

Given that shape of house is rectangular.

formula to calculate perimeter of rectangle can be used which is 2*(L+B)

where L is length of rectangle and B width of rectangle

Let the L and B be length of rectangular side of house

According to question

length of house is 10 feet less than twice the width of house

mathematically it can be represented as

L = 2*B - 10  --->eq. 1

Perimeter of house = 136 feet

using formula of Perimeter of rectangle

136 = 2*(L+B)

substituting the value of length in terms of width from eq. 1 in formula of perimeter

=> 136/2 = 2*B - 10 + B  (2*B+ B = 3B)

=> 68 = 3*B - 10

=> 78 = 3*B

B = 78/3 = 26

Therefore B which is width = 26 CM

length = 2*B - 10= 26*2 - 10 = 52-10=42

length of house = 42  cm

Hence dimension of Brian's house is length 42 cm and width 26 cm

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3 years ago
Which of the following is the solution to the compound inequality below?
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b. x ≥-2 or x ≤-6

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