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Maru [420]
3 years ago
12

What set of transformations are applied to parallelogram ABCD to create A'B'C'D'?

Mathematics
2 answers:
Verdich [7]3 years ago
7 0

Solution:

The information about the two parallelograms, one called Pre image (A B CD) and other called image (A'B'C'D').

Parallelogram formed by ordered pairs A at negative 4, 1, B at negative 3, 2, C at negative 1, 2, D at negative 2, 1. Second parallelogram transformed formed by ordered pairs A prime at negative 4, negative 1, B prime at negative 3, negative 2, C prime at negative 1, negative 2, D prime at negative 2, negative 1.

→As, the distance between X axis , that is distance of Preimage from X axis is same as distance of image from X axis.So,it is case of reflection over X axis.

→The two parallelogram ABCD and A'B'C'D' are congruent.So,Dilation hasn't taken place.Nor translation.

Option (B) →Reflected over the y-axis and rotated by 180° might be true.

pentagon [3]3 years ago
6 0

Answer: <u><em>Option (B)</em></u> →Reflected over the y-axis and rotated by 180° might be true.

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Type the correct answer in the box
algol13

c = cost of food/med for cats

d = cost of food/med for dog

y = total cost/spent

What you know:

y = 6c + d              [has 6 cats and 1 dog]  

c = 2/3d - 5        [cost for cat is 5 less than 2/3 cost for dog]

y = $195

y = 6c + d    

Substitute/plug in what you know, plug in (2/3d - 5) for c and 195 for y

195 = 6(2/3d - 5) + d        Distribute/multiply 6 into (2/3d - 5)

195 = 4d - 30 + d        Combine like terms

195 = 5d - 30      Add 30 on both sides of the equation

225 = 5d        Divide 5 on both sides

$45 = d            

5 0
3 years ago
Show the working out too please in numbers, thank you.
vazorg [7]

Hii :))

\tt \: - 5 =  \frac{x}{6}  \\   \tt \:  - 5 \times 6 = x \\  \boxed{  \tt \:  - 30 = x}

__________________

  • The correct value of x is <u>-</u><u> </u><u>3</u><u>0</u><u>.</u>

\overbrace{ \underbrace{ \sf \: \infty  \:  Carry \: on \: Learning \:  \infty }}

ᴛʜᴇᴇxᴛʀᴀᴛᴇʀᴇꜱᴛʀɪᴀʟ

3 0
3 years ago
Read 2 more answers
Simplify this expression 3-(7a+1)
Vinil7 [7]
3 - (7a + 1) =
3 - 7a - 1 =
-7a + 2 <===
5 0
4 years ago
Solve this query plzzz​
Olin [163]

Step-by-step explanation:

\frac{\sin \:4A}{\cos \:2A}  \times \frac{1 - \cos \:2A}{1 - \cos\:4A}   = \tan \:A \\  \\ LHS =  \frac{\sin \:4A}{\cos \:2A}  \times \frac{1 - \cos \:2A}{1 - \cos\:4A}   \\  \\  =  \frac{2\sin \:2A.\cos \:2A}{\cos \:2A}   \times  \frac{1 - (2 { \cos}^{2}A - 1) }{1 - (2 { \cos}^{2}2A - 1) } \\  \\  = 2\sin \:2A   \times  \frac{1 - 2 { \cos}^{2}A  +  1}{1 - 2 { \cos}^{2}2A  + 1 } \\  \\  = 2\sin \:2A   \times  \frac{2- 2 { \cos}^{2}A  }{2 - 2 { \cos}^{2}2A   } \\  \\   = 2\sin \:2A   \times  \frac{2(1 - { \cos}^{2}A)  }{2 (1-  { \cos}^{2}2A)   } \\  \\   = 2\sin \:2A   \times  \frac{1 - { \cos}^{2}A}{1-  { \cos}^{2}2A   } \\  \\     = 2\sin \:2A   \times  \frac{ { \sin}^{2}A}{{ \sin}^{2}2A   } \\  \\    = 2  \times  \frac{ { \sin}^{2}A}{{ \sin}2A   } \\  \\   = 2  \times  \frac{ { \sin}^{2}A}{{ 2\sin}A. \cos \:   A } \\  \\   = \frac{ { \sin}A}{ \cos \:   A }  \\  \\  = tan \: A \\  \\  = RHS \\

7 0
4 years ago
How is the graph of y=(x-1)2-3 transformed to produce the graph of Y = 3(x+4)?,
liubo4ka [24]

Answer

3412

Step-by-step explanation:

7 0
2 years ago
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