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Maru [420]
3 years ago
12

What set of transformations are applied to parallelogram ABCD to create A'B'C'D'?

Mathematics
2 answers:
Verdich [7]3 years ago
7 0

Solution:

The information about the two parallelograms, one called Pre image (A B CD) and other called image (A'B'C'D').

Parallelogram formed by ordered pairs A at negative 4, 1, B at negative 3, 2, C at negative 1, 2, D at negative 2, 1. Second parallelogram transformed formed by ordered pairs A prime at negative 4, negative 1, B prime at negative 3, negative 2, C prime at negative 1, negative 2, D prime at negative 2, negative 1.

→As, the distance between X axis , that is distance of Preimage from X axis is same as distance of image from X axis.So,it is case of reflection over X axis.

→The two parallelogram ABCD and A'B'C'D' are congruent.So,Dilation hasn't taken place.Nor translation.

Option (B) →Reflected over the y-axis and rotated by 180° might be true.

pentagon [3]3 years ago
6 0

Answer: <u><em>Option (B)</em></u> →Reflected over the y-axis and rotated by 180° might be true.

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What is a solution for 11/12
elena-s [515]

Answer:

It is either 11/12 or 0.91666666667.....

Step-by-step explanation:

Because this can not be actually divided into a "number" like 2 or 5, we can only get a approximate. Like the top answer.

Round to the nearest ten is 0.9

Round it to nearest hundredths is 0.92

7 0
2 years ago
Find the coordinates of C' after a reflection across the line
iragen [17]
<h3>Answer:  (4,2)</h3>

==============================================================

Explanation:

C is at (0,0). Ignore the other points.

Reflecting over y = 1 lands the point on (0,2) because we move 1 unit up to arrive at the line of reflection, and then we keep going one more unit (same direction) to complete the full reflection transformation. I'll call this point P.

Then we reflect point P over the line x = 2 to arrive at the location Q = (4,2). Note how we moved 2 units to the right to get to the line of reflection, and then keep moving the same direction 2 more units, then we have applied the operation of "reflect over the line x = 2"

So we have started at C = (0,0), moved to P = (0,2) and then finally arrived at the destination Q = (4,2). This is the location of C' as well.

All of this is shown in the diagram below.

4 0
3 years ago
10$ is spent on 2 big pails and 1 small one. A smail pail cosf half as much as each big one. How much is spent on a big pail? Ho
Mila [183]

Answer:

<u>$4</u> is spent on a big pail and <u>$2</u> is spent on a small pail.

Step-by-step explanation:

Given:

10$ is spent on 2 big pails and 1 small one.

A small pail cost half as much as each big one.

Now, to find the amount spent on a big pail and on a small pail.

Let the cost of a big pail be x.

And the cost of small pail be \frac{x}{2} .

As given, there are 2 big pails.

And the total money spent = $10.

According to question:

(x+x)+\frac{x}{2}=10

2x +\frac{x}{2}=10

\frac{4x+x}{2} =10

\frac{5x}{2} =10

<em>Multiplying both sides by 2 we get:</em>

5x=20

<em>Dividing both sides by 5 we get:</em>

x=4.

<em>The cost of a big pail</em> = $4.

<em>So, the cost of a small pail</em> = \frac{x}{2} =\frac{4}{2}=\$2.

Therefore, $4 is spent on a big pail and $2 is spent on a small pail.

6 0
3 years ago
2x≥12 <br>I can't figure this out ​
Serhud [2]

Answer:

x \geq 6

Step-by-step explanation:

You can start by dividing both sides by 2, getting x \geq 6.

7 0
2 years ago
Read 2 more answers
The sum of two numbers is 24 and their difference is 2?
mote1985 [20]
X + y = 24
x - y = 2

Adding both equations
2x = 26
x = 13
y = 11

7 0
3 years ago
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