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Maru [420]
3 years ago
12

What set of transformations are applied to parallelogram ABCD to create A'B'C'D'?

Mathematics
2 answers:
Verdich [7]3 years ago
7 0

Solution:

The information about the two parallelograms, one called Pre image (A B CD) and other called image (A'B'C'D').

Parallelogram formed by ordered pairs A at negative 4, 1, B at negative 3, 2, C at negative 1, 2, D at negative 2, 1. Second parallelogram transformed formed by ordered pairs A prime at negative 4, negative 1, B prime at negative 3, negative 2, C prime at negative 1, negative 2, D prime at negative 2, negative 1.

→As, the distance between X axis , that is distance of Preimage from X axis is same as distance of image from X axis.So,it is case of reflection over X axis.

→The two parallelogram ABCD and A'B'C'D' are congruent.So,Dilation hasn't taken place.Nor translation.

Option (B) →Reflected over the y-axis and rotated by 180° might be true.

pentagon [3]3 years ago
6 0

Answer: <u><em>Option (B)</em></u> →Reflected over the y-axis and rotated by 180° might be true.

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Answer:

a 0.5

b 0.4831

c 0.4354 < P < 0.53008

Step-by-step explanation:

Given that :

Probability (P) of a head or a tail when a coin is being tossed or flipped = 1/2 = 0.5

Sample size (n) = 296

Selected sample (X) = 143

a) Given that Emily used a coin toss to select either her right hand or her left hand, what proportion of correct responses would be expected if the touch therapists made random guesses?

The  proportion of correct responses that would be expected if the touch therapists made random guesses is 0.5

b) Using Emily's sample results, what is the best point estimate of the therapists' success rate?

Point estimate (p') = \frac{X}{n}

= (p') = \frac{143}{296}

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c) Using Emily's sample results, construct a 90% confidence interval estimate of the proportion of correct responses made by touch therapists.

The Z_c for 90% is 1.645

Using the formula P" -E < P < P" + E

where E = margin of error :  Z_c * \sqrt{\frac{P(1-P)}{n} }

=1.645 * \sqrt{\frac{0.4831(0.5169)}{296} }

=1.645 * \sqrt{\frac{0.2497}{296} }

=1.645*0.029

= 0.0477

∴ P" -E < P < P" + E

= 0.4831 - 0.0477 < P < 0.4831 + 0.0477

= 0.4354 < P < 0.53008

8 0
4 years ago
Find the value of 2a squared + 5b squared when a = -6 and b =2
jenyasd209 [6]

92

given 2a² + 5b²

substitute given values for a and b into the expression

2(- 6)² + 5(2)² = (2 × 36 ) + (5 × 4) = 72 + 20 = 92


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Answer:

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