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marissa [1.9K]
3 years ago
15

Mrs. Kennedy is buying pencils for each of 315 students. The pencils are sold in boxed of tens. How can she use rounding to deci

de how many pencils to buy?
Mathematics
1 answer:
ExtremeBDS [4]3 years ago
3 0
Mrs.Kennedy can divide 315 by 10 and then when she gets her answer she can round up to get her answer.
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this is a blueprint drawing of the stage area at Millennium Park the length of one square on the grid is equal to 5 feet accordi
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Answer:

No, diagonal of square C is 70.71ft

Step-by-step explanation:

Given in the question that length of one square = 5 ft

Length of Square C = 10 small squares

1 square = 5 ft

10 square = 5ft * 10

                = 50 ft

As we know that in a square all side are of equal length and make an angle of 90° at each corner.

So, by using pythagorus theorem

Diagonal of square² = side² + side²

Diagonal of square² = 2side²

Diagonal of square = √(2side²)

Diagonal of square = √2 (side)

where side = 50 ft

Diagonal of square = √2 (50)

Diagonal of square = 70.71 ft

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Bones Brothers & Associates prepare individual tax returns. Over prior years, Bones Brothers have maintained careful records
madreJ [45]

Answer:

For this case we have the following info related to the time to prepare a return

\mu =90 , \sigma =14

And we select a sample size =49>30 and we are interested in determine the standard deviation for the sample mean. From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the standard deviation would be:

\sigma_{\bar X} =\frac{14}{\sqrt{49}}= 2

And the best answer would be

b. 2 minutes

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

For this case we have the following info related to the time to prepare a return

\mu =90 , \sigma =14

And we select a sample size =49>30 and we are interested in determine the standard deviation for the sample mean. From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the standard deviation would be:

\sigma_{\bar X} =\frac{14}{\sqrt{49}}= 2

And the best answer would be

b. 2 minutes

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3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
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Simplify 18-2[x + (x - 5)].<br> O8-4x<br> 28 - 4x<br> 28 - 2x
densk [106]

Answer:

28-4x

Step-by-step explanation:

Step 1: Open most inner bracket and simplify

=18-2(x+x-5)

=18-2(2x-5)

Step 2: Expand brackets by multiplying 2 in and simplify

=18-2(2x)-2(-5)

=18-4x+10

=28-4x

Therefore the answer is 28-4x

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3 years ago
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