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motikmotik
3 years ago
6

Which expression is equivalent to 10a + 6? 10(a + 3) 2(5a + 3) 5(5a + 1) 10(a + 1)

Mathematics
2 answers:
Ivenika [448]3 years ago
6 0
Hey there!
We can factor 10a+6 to get our answer.
Remember factoring as the opposite of the distributive property
(i.e factored would by ab+ac and distributive would be a(b+c)).
We can't have <em>a</em> on the outside, since the second term in our expression doesn't contain an that variable.
We take our greatest common factor, or GCF, so it's factored completely.
We have:
2(5a+3).
Hopefully this helps
madreJ [45]3 years ago
5 0

Answer:

2(5a+3).

Step-by-step explanation:

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3 years ago
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A bank offers all savings accounts 5% interest compounded annually. If one account has a principal of $100 and another
arsen [322]

Answer:

From the calculation for both the accounts, it is clear that both the account double in the same time period of 14 years 26 days .

Step-by-step explanation:

Given as :

The principal for the first account = p = $100

The rate of interest = r = 5% compounded annually

The account gets double , so, Amount = A = $200

Let the time after which account gets double = t years

So<u>, From Compound Interest method</u>

Amount = Principal × (1+\dfrac{\trxtrm rate}{100})^{\textrm time}

As amount is double its principal

So, A = 2 × $100 = $200

Or, A = p × (1+\dfrac{\trxtrm r}{100})^{\textrm t}

Or, $200 = $100 × (1+\dfrac{\trxtrm 5}{100})^{\textrm t}

Or, \dfrac{200}{100} = (1.05)^{\textrm t}

Or, 2 = (1.05)^{\textrm t}

Taking Log both side

Log_{10}2 = Log_{10}(1.05)^{t}

Or, 0.3010 = t Log_{10}1.05

Or, 0.3010 = t × 0.0211

∴ t = \dfrac{0.3010}{0.0211}

I.e t = 14.26

So, The time period to get account double is 14 years 26 days

<u>Again </u>

Amount = Principal × (1+\dfrac{\trxtrm rate}{100})^{\textrm time}

Or, A = p × (1+\dfrac{\trxtrm r}{100})^{\textrm t}

As amount is double its principal

So, A = 2 × $1000 = $2000

Or, $2000 = $1000 × (1+\dfrac{\trxtrm 5}{100})^{\textrm t}

Or, \dfrac{2000}{1000} = (1.05)^{\textrm t}

Or, 2 = (1.05)^{\textrm t}

Taking Log both side

Log_{10}2 = Log_{10}(1.05)^{t}

Or, 0.3010 = t Log_{10}1.05

Or, 0.3010 = t × 0.0211

∴ t = \dfrac{0.3010}{0.0211}

I.e t = 14.26

So, The time period to get account double is 14 years 26 days

Hence From the calculation for both the accounts, it is clear that both the account double in the same time period of 14 years 26 days . Answer

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3 years ago
I need some help please
lesya [120]
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Answer:

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