For this case we must solve the following equation:
We apply distributive property on the right side of the equation:
We subtract 6y on both sides of the equation:
We subtract 6 from both sides of the equation:
Dividing by 6 on both sides of the equation:
So, the result is
Answer:
Answer: a. x=4 b. x=17.5
Step-by-step explanation:
a. 5x/2+1=11
subtract 1 from both sides : 5x/2=10
multiply both sides by 2 : 5x=20
divide both sides by 4 : x=4
b. 2x/7-3=2
add 3 to both sides : 2x/7=5
multiply both sides by 7 : 2x=35
divide both sides by 2 : x=17.5
Answer:
Two consecutive integers are of the form
x and x + 1
Their product is equal to 56
x(x + 1) = 56
Solve and find the two numbers x and x + 1. The above equation may be written as follows
x2 + x - 56 = 0
Factor and solve
(x - 7)(x + 8) = 0
solutions: x = 7 , x = -8
x= - 8 is not valid since the number sought must be positive. Hence
x = 7 and x + 1 = 8 are the two consecutive numbers.
Step-by-step explanation:
. x + (x + 2)≤166
. 2x+2≤166
. x≤83 - 1
. x≤82
. x=81
. 81+(81+2)=164; 164<166
answer: 81 and 83
