Perfect application for the Law of Cosines.
c^2 = a^2 + b^2 - 2ab cos C; here we want C, the angle opposite the 14 m side.
(14 m)^2 = (8 m)^2 + (12 m)^2 - 2(8 m)(12 m) cos C
196 = 64 + 144 - 192 cos C
-12 = -192 cos C, or cos C = 0.0625
Then C = arccos 0.0625 = 1.5083 radians
1.5083 radians 180 deg
= ----------------------- * -------------------
1 3.14159 rad
= 86.417 degrees
= 86 degrees, when rounded off as specified.
To answer the question above, determine the velocity of the car at time zero. To do such, determine the increase in velocity every hour (acceleration).
a = (62 - 53) / (6 -3) = 3 km/ h^2
Calculate for the initial velocity (v) by using either of the velocities paired with the corresponding time,
v = 53 km/h - (3 km/h^2) x 3 h = 44 km/h
The equation is <em>y = 44 + 3x</em>. Where x is the time in hours, y is the velocity in km/h.
Answer:
19
Step-by-step explanation:
just 19
Answer:
$2.48
Step-by-step explanation:
He paid $20 and got $12.56 back so you subtract
20-12.56=7.44
So his total was 7.44 and he bought 3 bags so divide to find the individual price
7.44/3=2.48
So $2.48
