Question

Find the value of sin² R

Answer 1

If the hypotenuse of PQR triangle is 5 and perpendicular is $\sqrt{2}$,then value of sin²R is 2/25.

Given that the hypotenuse is 5 and perpendicular is $\sqrt{2}$.

We are required to find the value of sin²R.

Trigonometric ratios are basically the ratios of the sides of the right angled triangle.

Sin is the ratio of perpendicular and hypotenuse of the right angled triangle. We can easily find the value of sin²R with the help of ratio of perpendicular and hypotenuse.

sin R=PQ/PR

sin R=$\sqrt{2}$/5

Squaring both sides,

sin² R=$(\sqrt{2} )^{2}$/$(5)^{2}$

sin²R=2/25

Hence if the hypotenuse is 5 and perpendicular is $\sqrt{2}$,then value of sin²R is 2/25.

Learn more about trigonometric ratios at brainly.com/question/24349828

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