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Len [333]
2 years ago
15

Find the value of sin² R

Mathematics
1 answer:
Vlada [557]2 years ago
8 0

If the hypotenuse of PQR triangle is 5 and perpendicular is \sqrt{2},then value of sin²R is 2/25.

Given that the hypotenuse is 5 and perpendicular is \sqrt{2}.

We are required to find the value of sin²R.

Trigonometric ratios are basically the ratios of the sides of the right angled triangle.

Sin is the ratio of perpendicular and hypotenuse of the right angled triangle. We can easily find the value of sin²R with the help of ratio of perpendicular and hypotenuse.

sin R=PQ/PR

sin R=\sqrt{2}/5

Squaring both sides,

sin² R=(\sqrt{2} )^{2}/(5)^{2}

sin²R=2/25

Hence if the hypotenuse is 5 and perpendicular is \sqrt{2},then value of sin²R is 2/25.

Learn more about trigonometric ratios at brainly.com/question/24349828

#SPJ1

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Answer:

Step-by-step explanation:

Angle PRS and RPQ are right angles. Segment SP is also congruent to segment QR. This means that triangle PRS and RPQ are right angle triangles.

Segment SP and segment QR are the longest sides and thus, the hypotenuse of each triangle. It means that the hypotenuse are congruent

The hypotenuse leg theorem states that any two right triangles are congruent if they have a congruent hypotenuse and a corresponding congruent leg. Therefore,

Angle PSR is congruent to angle RPQ and

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If six cookies cost the same as 2 brownies, and four brownies cost the same as 10 cupcakes, how many cupcakes can Bob buy for th
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