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mamaluj [8]
11 months ago
6

During what time interval was the object traveling most quickly?

Physics
1 answer:
anygoal [31]11 months ago
3 0

ANSWER

0s to 3s

EXPLANATION

To find the time interval where the object was traveling more quickly, we have to find the velocity of the object during each interval.

From a position-time graph, we can obtain the velocity of the object from the slope of the graph in each interval. To find those slopes, we just have to divide the vertical difference by the time interval.

The interval from 0s to 3s:

v=\frac{7-3}{0-3}=-\frac{4}{3}m/s

The interval from 3s to 5s and the interval from 7s to 8s have a horizontal line, so the slope is zero and therefore the velocity is zero - meaning that the object was not moving during these periods.

The interval from 5s to 7s,

v=\frac{5-3}{7-5}=\frac{2}{2}=1m/s

And the interval from 8s to 12s,

v=\frac{0-5}{12-8}=-\frac{5}{4}m/s

Two of these three velocities are negative. Negative velocity indicates that the object is moving backward.

From these velocities, the greatest one, in absolute value, is the one between 0s to 3s. During this interval, the object is moving backward but at the greatest velocity.

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Answer:

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1. A spring extends by 10 cm when a mass of 100 g is attached to it. What is the spring constant? (Calculate your answer in N/m)
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Answer:

1) k = 10 [N/m]

2) a-) x = 0.4 [m]

b)  x = 0.075 [m]

Explanation:

To be able to solve this type of problems that include springs we must use Hooke's law, which relates the force to the deformed length of the spring and in the same way to the spring coefficient.

F = k*x

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F = force [N] (units of Newtons]

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Now, the weight is equal to the product of the mass by the gravity

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2)

a ) if the force is 4 [N]

clearing x

x = F/k

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Solving for acceleration requires diving all terms by the mass, so:

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