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4 years ago

Using Figure 25-2, determine how Giant stars differ from main sequence stars.

Physics

2 answers:

erastova [34]4 years ago

8 0

Main sequence stars lay on a diagonal going from upper left angle to lower right angle. Part of main sequence is our Sun.

When we observe this diagram we need to compare giant stars and main sequence stars. GIant stars are positioned to upper right when compared to main sequence. From labels on coordinate axis we can see that giant stars generaly have lower temperature than main sequence stars. They also have higher brightness and lower magnitude (meaning that they are more bright in night sky).

lora16 [44]4 years ago

6 0

Answer:

Giant stars differ from main sequence stars in having greater absolute magnitudes for the same temperatures.

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In which scenario will an athlete's wrists be under tension?

Oxana [17]

Answer:

I think the answer would be D.

Explanation:

It could be b or d, the reason that I think that it is d is because lifting does not directly involve your wrist.

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3 years ago

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An object with a mass M = 250 g is on a plane inclined at 30º above the horizontal and is attached by a string to a mass m = 150

malfutka [58]

Answer:

0.495 m/s

Explanation:

$T$ = tension force in the string connecting the two objects

$M$ = Mass of the object on inclined plane = 250 g = 0.250 kg

$m$ = Mass of the hanging object = 150 g = 0.150 kg

$a$ = acceleration of each object

From the force diagram, force equation for the motion of the object on the inclined plane is given as

$T - Mg Sin30 = Ma\\T = Mg Sin30 + Ma$

From the force diagram, force equation for the motion of the hanging object on the inclined plane is given as

$mg - T = ma\\T = mg - ma$

Using the above two equations

$Mg Sin30 + Ma = mg - ma$

$(0.250)(9.8) Sin30 + (0.250) a = (0.150) (9.8) - (0.150)a$

$a = 0.6125 ms^{-2}$

$h$ = height dropped by the hanging object = 10 cm = 0.10 m

$v$ = Speed gained by the object

Speed gained by the object can be given as

$v = sqrt(2ah)\\v = sqrt(2(0.6125)(0.20))\\v = 0.495 ms^{-1}$

5 0

3 years ago

A group of students is investigating whether the smoothness of surface affects the force of friction. Each student pushes a book

Pani-rosa [81]

To find the average (aka mean) of a group of numbers, all we need to do is add them up then divide that number by how many numbers we started with

23 + 21 + 24 + 22 = 90

90 ÷ 4 = 22.5

Therefore, the average distance the book traveled on ice is 22.5 cm

15 + 18 + 16 + 17 = 66

66 ÷ 4 = 16.5

Therefore, the average distance the book traveled on concrete is 16.5 cm

In conclusion, the average distance the book traveled on ice is greater than the average distance the book traveled on concrete

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4 years ago

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The graphs display velocity data. Velocity is on the y-axis (m/s), while time is on the x-axis (s). Based on the graphs,

EastWind [94]

Answer:

0 1 2 3 4 . because the particle moved with a constant acceleration

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2 years ago

When a light bulb is connected to a 4.5 V battery, a current of 0.16 A passes through the bulb filament. What is the resistance

larisa [96]

Answer:

R = 28.125 ohms

Explanation:

Given that,

The voltage of a bulb, V = 4.5 V

Current, I = 0.16 A

We need to find the resistance of the filament. Using Ohm's law,

V = IR

Where

R is the resistance of the filament

So,

$R=\dfrac{V}{I}\\\\R=\dfrac{4.5}{0.16}\\\\R=28.125\ \Omega$

So, the resistance of the filament is equal to 28.125 ohms.

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3 years ago