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yawa3891 [41]
3 years ago
13

Two objects have the same size and shape, but one is much heavier than the other. When they are dropped simultaneously from a to

wer, they reach the ground at the same time (assuming that there is no air resistance), but the heavier one has a greater
speed
acceleration
none of the above
all of these
Physics
1 answer:
maria [59]3 years ago
6 0

Answer:

None of the above.

The correct answer would be momentum

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How much soil is in a 5 cm to 9 cm deep hole?
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There is no soil in a hole

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3 years ago
A piece of toast weighing 8 grams is flying through the air at 15
Ket [755]

The kinetic energy of toast is 0.06 J.

<u>Explanation:</u>

Kinetic energy is the way to determine the energy released when an object is in motion. In other times, it can be the energy required to move any object and to make it in motion.

As the mass of the toast is given as 8 g and speed is given as 15 m/s, if we ignore the friction caused by air molecules. Then the kinetic energy is the product of mass and square of velocity.

K.E. = \frac{1}{2} × mass × v²

Kinetic energy =\frac{1}{2} \times \frac{8}{1000} \times 15

Since, the weight is given in grams , it needed to be converted into kg.

Kinetic energy = 0.06 J

Thus, the kinetic energy of toast is 0.06 J.

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3 years ago
A particle is projected from a point on a horizontal plane and has an initial velocity of 28root 3 m/s at an angle of 60 degree
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4 0
3 years ago
Cart a having a mass of 150 kg initially moving to the right at a speed of 8 m/s collides with cart b with a mass of 150 kg, ini
kakasveta [241]

The speed of cart b is 6m/s while the total momentum of the systmen is 4200 kg m/s

<h3>Conservation of Linear Momentum</h3>

Given Data

  • Mass of cart one M1  = 150kg
  • Initial Velocity U1 = 8m/s
  • Final VelocityV1 = 5 m/s

Mass of cart two M2  = 150kg

Velocity U2 = 6m/s

Applying the principle of conservation of linear momentum we have

M1U1+M2U2 = M1V1+ M2V2

a. what is the speed of cart b after collision

substituting our given data we have

150*8+ 150*6 = 150*5+150*V2

1200 + 900 = 1200+ 150V2

2100 - 1200 = 150V2

900 = 150V2

Divide both sides by 150

V2 = 900/150

V2 = 6m/s

b. what is the total momentum of the system before and after collision

Total Momentum in the system is

Total momentum = Momentum before Impact+ Momentum after Impact

Total momentum = M1U1+M2U2 + M1V1+ M2V2

Total momentum = 1200 + 900 + 1200+ 900

Total momentum = 4200 kg m/s

Learn more about Conservation of Linear Momentum here:

brainly.com/question/7538238

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2 years ago
Which of the following items best embodies the physical property of conductivity?
Ostrovityanka [42]

Copper penny is the answer

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