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Ganezh [65]
4 years ago
9

The number 3 in hydrogen in NH33 is the

Physics
1 answer:
frosja888 [35]4 years ago
4 0

Answer:

no of atoms

Explanation:

for each amonia molecule one nitrogen atom bind with 3 hydrogen atoms

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1. Which of the choices will make a brass band?
yuradex [85]

Explanation:

1.

C. Bamboo woodwind instrument

2.

C. Flute

3.

A. Bass Drum

4 0
3 years ago
Current is constant at all points in a parallel circuit.<br><br> True<br> False
Sergio [31]
This is false. Current is the speed of the charge, 1 amp of current is 1 coulomb per second. So you can imagine the current of a circuit as the current of a river. In a parallel circuit, the river breaks into two separate streams. Some of the water goes down one river, some goes down the other. However, the total amount of water/coulombs never changes. This means that some of the total current will go down one river, and one the other. However, with less coulombs now the current will decrease. 

Long story short, since there are two paths, the charge will split and depending on the resistance of each parallel stream a different amount of charge will go down each branch.  
5 0
3 years ago
4. How long does it take a car traveling at 45 km/h to travel 100.0 m?<br> 4500m
Trava [24]

Answer:

8.0s

Explanation:

45 km/h ÷ 3.6  = 12.5 m/s

t.v = d/t

vt/v = d/v

t = d/v = 100.0m /12.5 m/s = 8.0s

Hope this helps!!

8 0
3 years ago
9. A current of 9 A flows through an electric device with a resistance of 43 Ω. What must be the applied voltage in this particu
kotykmax [81]

Voltage =Current * Resistance

             = 9 * 43

Voltage = 387 V

6 0
3 years ago
A force of 6.0 N is applied horizontally to a 3.0 kg crate initially at rest on a horizontal frictionless surface. After the cra
Savatey [412]

Answer:

a. Yes, because the acceleration of the crate is 2.0 m/s².

Explanation:

Given

Force = 6N --- f

Mass = 3kg --- m

Time = 1.5s --- t

Velocity = 3.0m/s --- v

Required

Does the system support F=ma

Yes, it does and this is shown below

The crate is initially at rest; so:

u = 0

Using the first equation of motion

v = u + at

Substitute values for v, u and t

3 = 0 + a*1.5

3 = 1.5a

Make a the subject

a = 3/1.5

a = 2

Using F = ma

Substitute values for F and m

6 = 3 * a

Divide both sides by 3

6/3 = 3/3 * a

2 = a

a = 2

In both cases:

a = 2

<em>Hence, option (a) is correct.</em>

6 0
3 years ago
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