All cross sections of spheres are “circles”
By definition of conditional probability,
Similarly,
Hi I think it would be zero sense the object is in one spot. I hope I helped
The probability of one head and one tail is 2/3.
<u>Step-by-step explanation</u>:
- The possibilities for flipping two fair coins are {T,T}, {H,H}, {H,T}, {T,H}
- Given the case that at least one coin lands on a head, So the total possibilities are {H,H}, {H,T}, {T,H} = 3 possibilities
- Required event is 1 head and 1 tail= {H,T}, {T,H} = 2 possibilities
To calculate the probability of one head and one tail,
Probability = required events / Total events
Probability = 2/3
Answer:
0.0728177272
Step-by-step explanation:
Given :
Number of flips = 80
Probability of landing on tail at most 33 times ;
Probability of landing on tail on any given flip = 1 / 2 = 0.5
This a binomial probability problem:
Hence ;
P(x ≤ 33) = p(x=0) + p(x=1) +... + p(x = 33)
Using a binomial probability calculator :
P(x ≤ 33) = 0.0728177272
