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2 years ago

I don’t understand this question. 9th, 10th, 11th, and 12th subpart questions, please.

Physics

1 answer:

Lerok [7]2 years ago

6 0

The warm air over the beach rises while the cooler denser air rushes in due to the transfer of heat through the air by the convection process.

Thus, convection is the correct answer to the 9th question.

The heat travels from the marshmallow to the screwdriver which is in contact with the marshmallow. This process is the conduction process.

Thus, conduction is the correct answer to the 10th question.

The hair curler transfers the heat to the hair which is in contact with the curler.

This process of transfer of heat is known as the conduction process.

Thus, conduction is the correct answer to the 11th question.

The body of the person is in contact with the rock. Thus, the transfer of heat takes place due to conduction.

Thus, conduction is the correct answer to the 12th question.

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3 years ago

Read 2 more answers

A potential difference of 300 volts is applied to a 2.0-µf capacitor and an 8.0-µf capacitor connected in series. (a) What are t

zubka84 [21]

Answer:

a) Q1=Q2=480μC V1=240V V2=60V

b) Q1=96μC Q2=384μC V1=V2=48V

c) Q1=Q2=0C V1=V2=0V

Explanation:

Let C1 = 2μC and C2=8μC

For part (a) of this problem, we know that charge in a series circuit, is the same in C1 and C2. Having this in mind, we can calculate equivalent capacitance first:

$C=\frac{1}{\frac{1}{C1} +\frac{1}{C2} } = 1.6\mu C$

$Q_{T} = V_{T}*C_{T} = 480\mu C$

$V1 = \frac{Q1}{C1}=240V$

$V2 = \frac{Q2}{C2}=60V$

For part (b), the capacitors are in parallel now. In this condition, the voltage is the same for both capacitors:

$V1=V2$ So, $\frac{Q1}{C1} = \frac{Q2}{C2}$

Total charge is the same calculated for part (a), so:

$\frac{Qt - Q2}{C1} = \frac{Q2}{C2}$ Solving for Q2:

Q2 = 384μC Q1 = 96μC.

Therefore:

V1=V2=48V

For part (c), both capacitors would discharge, since their total voltage of 300V would by applied to a wire (R=0Ω). There would flow a huge amount of current for a short period of time, and capacitors would be completely discharged. Q1=Q2=0C V1=V2=0V

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3 years ago

What must be true in order for magnetism to induce an electric current in a wire?

worty [1.4K]

Answer:

The wire must be part of a closed circuit.

Explanation:

A closed circuit in electric is what we called a wire that has a complete electrical connection in which electricity flows, where electric current flow from one end to another, in order for magnetism to induce an electric current the circuit has to be closed, or no current will flow.

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2 years ago

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My calculations state, not rounding, the mass is 1.8

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