Explanation:
Looking at the placement of primary colors in the RGB color wheel, the mixing of the red and green colors will create Yellow secondary color.
Explanation:
I'm not sure, but I would go for the more than A since its orbital speed is at its fastest and the sweep occurs in about the same period of days.
Answer: 4.29 m/s
Explanation:
Given
Depth of the well, s = 8.23 m
Time taken to reach the well, t = 0.93 s
Speed of sound = 343 m/s
To solve this, we would be using one of l the laws of motion.
S = ut + 1/2gt², where
S = depth of the well
u = initial speed of toss
g = acceleration due to gravity
t = time taken to reach the well
We would then have
8.23 = 0.93 u + 1/2 * 9.8 * 0.93²
8.23 = 0.93 u + 4.9 * 0.8649
8.23 = 0.93 u + 4.23801
0.93 u = 8.23 - 4.23801
0.93 u = 3.99199
u = 3.99199 / 0.93
u = 4.29 m/s
Therefore, the initial speed of the coin is 4.29 m/s
The force that a moving object exerts on another object upon colliding with it is rather the change in momentum divided by the amount of time elapsed during the collision.
F = Δp/Δt
F = force, Δp = change in momentum, Δt = elapsed time
Usually we say momentum is proportional to mass instead of saying momentum is proportional to weight. But sure, for two objects on the same planet, greater weight implies greater mass. Momentum is the product of mass and velocity:
p = mv
p = momentum, m = mass, v = velocity
So we have two identical cars on the same planet with one car traveling 30mph faster than the other. Let's say they both collide with a tree, both coming to a rest, and the collisions take the same amount of time to happen. The faster car loses a greater amount of momentum over the same amount of time, therefore delivering a greater force.
Choice B
<span>The most likely type of star to be found in the halo are stars classified as M stars. These stars absorb red light, have temperatures under 3000K, have an average mass of .3 times the mass of the sun, have an average radius of .4 times the radius of the sun, and have .04 times the luminosity of the sun.</span>
